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Nina [5.8K]
2 years ago
9

Solve the equqtion of a circle (-3,4) and radius 4 units​

Mathematics
2 answers:
Art [367]2 years ago
8 0

Step-by-step explanation:

The equation of a circle is usually in the form: (x-h)^2+(y-k)^2=r^2 where (h, k) is the center and r is the radius. With the information you provided you would have the equation: (x+3)^2+(y-4)^2=16. I'm a bit confused by "solve the equation of a circle" do you mean solve for y? if so you would just do

Original Equation:

(x+3)^2+(y-4)^2=16

Subtract (x+3)^2 from both sides

(y-4)^2=-(x+3)^2+16

Take the square root of both sides

y-4 = \pm\sqrt{-(x+3)^2+16}

add 4 to both sides

y=\pm(\sqrt{-(x+3)^2+16})+4

and then just change the sign to negative or positive depending on what half of the circle you want

AlladinOne [14]2 years ago
8 0

<u>Let's take this problem step-by-step</u>:

<u>I will assume that you want the </u><u><em>standard form of the equation of the circle</em></u>:

      ⇒ <em>standard form</em>: (x-h)^2 +(y-k)^2=r^2

  • (h,k) --> coordinate of circle's center --> (-3,4)
  • r --> length of radius --> 4

<u>LEt's plug in the known values</u>

   (x-(-3))^2+(y-4)^2 = 4^2\\(x+3)^2+(y-4)^2=16

<u>Answer: (x+3)² + (y-4)² = 16</u>

<u></u>

Hope that helps!

#LearnwithBrainly!

 

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