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3 years ago

which graph represents a function with the domain of all real numbers greater than or equal to -7 and less than 2

Mathematics

2 answers:

Readme [11.4K]3 years ago

5 0

Your answer should be D.......

zysi [14]3 years ago

5 0

Answer:

D.It is true because its domain of all real numbers greater than or equal to -7 and less than 2.

Step-by-step explanation:

We have to find that graph which represent a function whose domain of all real numbers :greater than or equal to -7 and less than 2.

A.Graph A does not represent that function because its domain of all real numbers greater than -2 and less than or equal to 7.It is not true.

B.Graph B does not represent that function because its domain of all real numbers greater than or equal to -4 and less than 1.

C.It is not true of all real numbers because its domain of all real numbers greater than or equal to -3 and less than 2.

D.It is true because its domain of all real numbers greater than or equal to -7 and less than 2.

Hence, option D is true.

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12. If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95% confident that th

atroni [7]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

Step-by-step explanation:

We have the following info given:

$Confidence= 0.95$ the confidence level desired

$ME =0.03$ represent the margin of error desired

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

The confidence level is 95% or 0.95, the significance is $\alpha=0.05$ and the critical value for this case using the normal standard distribution would be $z_{\alpha/2}=1.96$

Since we don't have prior information we can use $\hat p= 0.5$ as an unbiased estimator

Also we know that $ME =\pm 0.03$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

6 0

3 years ago

Use long division to express each fraction as a decimal

lawyer [7]

Answer:

Sorry what fraction

Step-by-step explanation:

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2 years ago

Read 2 more answers

How to factor completely 2x^2+19x+24

Gnom [1K]

2=2*1,1*2
24=1*24,2*12,6*4,3*8
19=2*8+3

2x²+19x+24
(2x+3)(x+8)

or
2x(x+8)+3(x+8)
2x²+16x+3x+24
2x²+19x+24

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3 years ago

Let X denote the temperature (degree C) and let Y denote thetime in minutes that it takes for the diesel engine on anautomobile

BlackZzzverrR [31]

Answer:

Step-by-step explanation:

Given $f_{XY} (x,y) = c(4x + 2y +1) ; 0 < x < 40\,and\, 0 < y$

we know that $\int\limits^\infty_{-\infty}\int\limits^\infty_{-\infty} {f(x,y)} \, dxdy=1$

therefore $\int\limits^{40}_{-0}\int\limits^2_{0} {c(4x+2y+1)} \, dxdy=1$

on integrating we get

c=(1/6640)

$P(X>20, Y>=1)=\int\limits^{40}_{20}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy$

on doing the integration we get

=0.37349

marginal density of X is

$f(x)=\int\limits^2_{0} {\frca{1}{6640}(4x+2y+1)} \, dy$

on doing integration we get

f(x)=(4x+3)/3320 ; 0<x<40

marginal density of Y is

$f(y)=\int\limits^{40}_{0} {\frca{1}{6640}(4x+2y+1)} \, dx$

on doing integration we get

$f(y)=\frac{(y+40.5)}{83}$

$P(01)=\int\limits^{40}_{0}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy$

solve the above integration we get the answer

$P(X>20, 0$

solve the above integration we get the answer

Two variables are said to be independent if there jointprobability density function is equal to the product of theirmarginal density functions.

we know f(x,y)

In the (c) bit we got f(x) and f(y)

f(x,y)cramster-equation-2006112927536330036287f(x).f(y)

therefore X and Y are not independent

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3 years ago

Is 5.35 a repeating decimal

Naya [18.7K]

If its just 5.35 then no. But if its a number like pie then yes.

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3 years ago

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