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http://googletune.com/watch?v=M5LUFjQkqDA
Every recursive function should have an exit criterion (=handling the base case) to exit the recursion.
Without it, it wil recurse forever, until system resources run out (typically the call stack will overflow and your program will crash).
MCSE is a Microsoft Certified Solutions Expert.
Answer:
The answer is Break
<u>Explanation:</u>
When break statement is occurred then, it immediately exits from the loop and executed the statement after the loop without raising any kind of error.
<u>The situation after entering of a value by a user
</u>
- If the user entered incorrect value then it will exit from the loop.
- If the user entered correct input value, then it will run the loop for the further values.
Answer:
import java.util.Scanner;
public class LabProgram {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int inputYear;
boolean isLeapYear;
isLeapYear = false;
inputYear = scnr.nextInt();
// If a year is divisible by 400, then it is a leap year
if (inputYear % 400 == 0)
isLeapYear = true;
// If a year is divisible by 100, then it is not a leap year
if (inputYear % 100 == 0)
isLeapYear = false;
// If a year is divisible by 4, then it is a leap year
if (inputYear % 4 == 0)
isLeapYear = true;
if(isLeapYear)
System.out.println(inputYear + " is a leap year.");
else
System.out.println(inputYear + " is not a leap year.");
}
}
Explanation:
- Take the year as an input from user and store it to inputYear variable.
- If the year is a century year, check if the year is divisible by 400 ( the year must be evenly divisible by 400 ), then set the boolean isLeapYear to true. If a year is divisible by 100, then set the boolean isLeapYear to false. If a year is divisible by 4, then set the boolean isLeapYear to true.
- Check if isLeapYear is true, then print that it is a leap year. Otherwise, print that it is not a leap year.
Output:
1712
1712 is a leap year.
