Answer:
Nope
Step-by-step explanation:
To now if a triangle is a right angle, use Pythagoras Theorem,
a^2 + b^2 = c^2
C usually be the longest side of the triangle, C = 17
Then also let a and b be 6 and 13 respectively.
6^2 + 13^2 =205
C^2 = 205
C = sqrt(205) = 14.32
therefore no this is not a right angle triangle
Step-by-step explanation:
Divide two on both sides to get rid of it and the make the equation in the form y = mx + c

y = 3/2x + 5
since both lines are parallel they must have the same gradient which is 3/2
y = 3/2x + c
All you have to do now is to replace x and y with (2, -5) to find c
x = 2
y = -5
-5 = 3/2 × 2 + c
-5 = 3 + c
c = -5-3
c = -8

Answer: there is only one solution
Step-by-step explanation:
Combine like terms by performing the opposite operation of subtracting 4x on both sides of the equation
The 4x's will cross out on the right
4x - 4x = 0x = 0
On the left:
2x - 4x = -2x
Now the equation looks like:
-2x + 3 = 2
Continue to combine like terms by subtracting 3 on both sides of the equation
On the left:
3 - 3 = 0
On the right:
2 - 3 = -1
Equation:
-2x = -1
Isolate x by performing the opposite operation of dividing -2 on both sides of the equation
On the left:
-2x ÷ -2 = 1
On the right:
-1 ÷ -2 = 1/2
x= 1/2
Answer:
12
Step-by-step explanation: