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sukhopar [10]
3 years ago
13

Can you please help me with 3 and 4

Mathematics
1 answer:
Otrada [13]3 years ago
3 0
Number 3 is 1:3 but I don't know what 4 is I can't see the whole problem
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If y=-8 when x=2, find y when x=3
tatuchka [14]

I don't really know if the question is complete but...

y = x -10    can be a solution

so y would be -7 when x is 3

7 0
3 years ago
Consider the system of linear equations and the matrix equations below.
gregori [183]

9514 1404 393

Answer:

  x = 7

Step-by-step explanation:

Using Cramer's rule, the value of x is ...

  x=\dfrac{\left|\begin{array}{cc}2&3\\22&-2\end{array}\right|}{\left|\begin{array}{cc}-1&3\\4&-2\end{array}\right|}

  x = ((2)(-2) -(22)(3))/((-1)(-2) -(4)(3)) = (-4-66)/(2-12) = -70/-10

  x = 7

4 0
3 years ago
What is your number?
Goryan [66]

Answer:

13 and 11

Step-by-step explanation:

how is helpful

5 0
3 years ago
Read 2 more answers
I need help with question 10 (math work is about adding fractions with putting them in simplest form)
goldenfox [79]

Answer: The answer is equivalent fractions.

Step-by-step explanation:

I hope this helped you! :D

8 0
3 years ago
How do I factor the quadratic equation
anastassius [24]
Factor the following:
10 y^2 - 35 y + 30
Factor 5 out of 10 y^2 - 35 y + 30:
5 (2 y^2 - 7 y + 6)
Factor the quadratic 2 y^2 - 7 y + 6. 
The coefficient of y^2 is 2 and the constant term is 6. 
The product of 2 and 6 is 12. 
The factors of 12 which sum to -7 are -3 and -4. So 2 y^2 - 7 y + 6 = 2 y^2 - 4 y - 3 y + 6 = y (2 y - 3) - 2 (2 y - 3):
5 y (2 y - 3) - 2 (2 y - 3)
Factor 2 y - 3 from y (2 y - 3) - 2 (2 y - 3):
Answer:  5 (2 y - 3) (y - 2)
4 0
3 years ago
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