Find the HCF of x 3 y 3 and y 4
1 answer:
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Quadratic equation is 
WHEN
So, to make this true subtract 7 from each side.
The equation is now 7
- x - 7 = 0
Values for a, b, and c: a = 7, b = -1, c = -7
Plug these variables into the quadratic equation.
Square -1 to get 1 and multiply -4 x 7 x -7 to get 196.
Multiply 2 x -7 to get -14, the denominator, and add 1 to 196.
Since 197 is not a square number, and I don't know if you want to leave it in radical form or not, I will just because it's easier to understand.
Hope this helps!
So, to make this true subtract 7 from each side.
The equation is now 7
Values for a, b, and c: a = 7, b = -1, c = -7
Plug these variables into the quadratic equation.
Square -1 to get 1 and multiply -4 x 7 x -7 to get 196.
Multiply 2 x -7 to get -14, the denominator, and add 1 to 196.
Since 197 is not a square number, and I don't know if you want to leave it in radical form or not, I will just because it's easier to understand.
Hope this helps!
x=(5*21)/7=15 taken spaces
total =empty spaces+taken spaces= 21+15=36