Ka aahuauauquauuahsbsakaiwuwushsbh
Answer:
im pretty sure the answer is 150
Step-by-step explanation:
hope this helps <3
Answer:

Step-by-step explanation:
so you already have the formula, which is
![\sqrt[3]{ \frac{3v}{4\pi} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3v%7D%7B4%5Cpi%7D%20%7D%20)
the v represents Volume.
and 3v would be 3×volume.
![\sqrt[3]{ \frac{3 \times 1000}{4 \times \pi} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%20%5Ctimes%201000%7D%7B4%20%5Ctimes%20%5Cpi%7D%20%7D%20)
![\sqrt[3]{ \frac{3000}{12.56637061} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3000%7D%7B12.56637061%7D%20%7D%20)
![\sqrt[3]{238.7324147 }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B238.7324147%20%7D%20)

to the nearest tenth place.

Step-by-step explanation:
General form of a conic section is:
Ax² + Bxy + Cy² + Dx + Ey + F = 0
If B = 0:
Parabola: Either x² or y² term, but not both
Circle: x² and y² have the same coefficient
Ellipse: x² and y² have different positive coefficients
Hyperbola: x² and y² have different signs
Otherwise, look at the discriminant.
If B² − 4AC < 0, then the conic is an ellipse.
If B² − 4AC = 0, then the conic is a parabola.
If B² − 4AC > 0, then the conic is a hyperbola.
Answer:
4. C) 
3. B) 9,6 = the number of points you would increase each hour of studying; 65,8 = your score if you studied 0 hours
2. B) The events have a strong positive linear correlation.
1. C) Find the slope using the slope formula:

Step-by-step explanation:
4. (−7, 10) → 10 = 7 + 3 ☑
(−1, 4) → 4 = 1 + 3 ☑
(0, 3) → 3 = 0 + 3 ☑
(3, −2) → −2 ≠ −3 + 3; 0 ☒
3. You obviously have to plug "0" in for x to get your initial value of 65,8, which represents the minimum value of points you would receive if you never were to study, and of course, the 9,6 is the average score increased for every hour studied.
2. The correlation coefficient is 0,02, which is positive, so this would be the obvious choice.
1. You CANNOT write a linear equation without FIRST finding the rate of change [slope]. You will ALWAYS need the rate of change in order to write any linear equation.
I am joyous to assist you anytime.