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devlian [24]
2 years ago
15

State two properties of sulphur that makes it possible to extract using the frasch process​

Chemistry
1 answer:
Wewaii [24]2 years ago
8 0

Explanation:

sulphur has a low melting point.

sulphur has a low boiling point thus it can be extracted by pumping hot water which turns it ito solution form

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A gas turns to liquid
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Figure 2 represents part of the structure of graphite.
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The answers include the following:

  • Graphite conducts electricity because it has delocalised electrons which makes it possible for the electrons to move freely.
  • Graphite is slippery because it has layers which makes it possible for the atoms to slide over each other.

<h3>What is Graphite?</h3>

This is referred to as an allotrope of carbon and it is the most stable form. it is used in the production of substances such as pencil, electrode etc.

Graphite is able to conduct electricity because of the presence of delocalized electrons and is slippery due to its atoms being able to slide over one another.

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1 year ago
How many atoms are in cuso4?
AnnZ [28]
There are 6 atoms in that compount
3 0
3 years ago
If an element has two or more atoms with the same number of protons but different number of neutrons it is called what
Oksana_A [137]
It’s called an isotope which is an atom with the same number of protons but a different number of neutrons
8 0
3 years ago
The heat capacity of water is 1cal degree'g1 (1 calorie per degree centigrade, per gram). You are given 1 gallon of water at 25
sdas [7]

Answer:

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

Explanation:

Q=mc\Delta T

Where:

Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance  

ΔT = change in temperature of the substance

We have :

Volume of water = V = 1 gal = 4546.09 mL

Density of water , d= 1 g/mL

mass of water = m = d × V = 1g/mL × 4546.09 mL =  4546.09 g

Specific heat of water = c = 1 Cal/g°C

ΔT = 100°C - 25°C = 75 °C

9 (boiling pint of water is 100°C)

Heat absorbed by the water to make it boil:

Q= 4546.09 g\times 1 Cal/g^oC\times 75^oC=340,956.75 Cal

1 calorie = 4.184 J

Q=\frac{340,956.75}{4.184} J = 81,490.62 J

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

5 0
3 years ago
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