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Chemistry

1 answer:

Step2247 [10]3 years ago

3 0

Answer:

B. is the answer.

Explanation:

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In this case, since the law of conservation of mass states that matter cannot be created nor destroyed, we infer that the correct answer must have the same number of atoms at both sides of the equation.

Therefore, we can see how B. has three white molecules as well as three black molecules at the reactants side and after the chemical reaction there are two molecules having a total of three of each molecule at the products side unlike the other choices; for that reason the correct answer is B.

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Read 2 more answers

Mercury(II) oxide (HgO) decomposes to form mercury (Hg) and oxygen (O2). The balanced chemical equation is shown below. 2HgO Rig

BigorU [14]

Taking into account the reaction stoichiometry, the correct answer is the third option: 15.63 moles of HgO are needed to produce 250 g of O₂.

In first place, the balanced reaction is:

2 HgO → 2 Hg + O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

HgO: 2 moles
Hg: 2 moles
O₂: 1 moles

The molar mass of the compounds is:

HgO: 216.59 g/mole
Hg: 200.59 g/mole
O₂: 32 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

HgO: 2 moles× 216.59 g/mole= 433.18 grams
Hg: 2 moles× 200.59 g/mole= 401.18 grams
O₂: 1 mole× 32 g/mole= 32 grams

Then the following rule of three can be applied: if by reaction stoichiometry 32 grams of O₂ are produced by 2 moles of HgO, 250 grams of O₂ are produced from how many moles of HgO?

$moles of HgO=\frac{250 grams of O_{2} x2 moles of HgO}{32grams of O_{2}}$