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loris [4]
2 years ago
8

Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options.

Mathematics
1 answer:
fenix001 [56]2 years ago
7 0

A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.

<h3>Which is the correct representation of the inequality?</h3>

Here we have.

-3(2x - 5) < 5*(2 - x)

First, we need to isolate x in one side, let's expand both sides:

-6x + 15 < 10 - 5x

15 - 10 < 6x - 5x

5 < x

This will be represented with a number line where we have an open circle at 5, and an arrow that goes to the right. So the correct option is:

"A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right."

If you want to learn more about inequalities:

brainly.com/question/18881247

#SPJ1

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Need to solve for Y by filling in the blanks<br>(y +44)°, 86, (3y)°​
lapo4ka [179]
Answer:

1.89

Solution:

We have -44x - 86 = -3

First, we move the non x terms to the RHS of the equation. To do this, we add 86 to both sides.

Note: if a = b, then a + c = b + c
Therefore, -44x - 86 + 86 = -3 + 86

or, -44x = 83

Next, divide both sides by -44, which is the coefficent of x

Note: if a = b, then a ÷ c = b ÷ c
-44x
-44
=
83
-44

or, x = -1.89


Explaination:

This is right I guess
4 0
3 years ago
When 27x^2z divided by -3x^2z^6 is correctly simplified, the exponent on the variable z is _____.
Dmitry_Shevchenko [17]
The Answer Is YES :D

6 0
3 years ago
Please help with these math questions I really need it ! Don't just do it for points pls
steposvetlana [31]

Answer:

wouldn't that be 81 but i dont know

3 0
3 years ago
Read 2 more answers
I need help (20 points)
Illusion [34]

Answer:

no they are not perpendicular

3 0
3 years ago
In triangle △ABC, ∠ABC=90°,
makvit [3.9K]
<h3>Answer: As a fraction, HC is 21/4 units long</h3><h3>In decimal form, HC is 5.25 units long.</h3>

==============================================

Work Shown:

Let x = HC and y = BH

AH = 12-x since AH = 12-HC and x = HC

---------------

See the attached drawing below. The altitude BH forms three similar triangles which makes the proportion below possible

HC/BH = BH/AH

x/y = y/(12-x) ... substitution

x(12-x) = y^2 ... cross multiply

y^2 = -x^2+12x

note how I isolated y^2 instead of y. We will use this equation later.

---------------

Focus on triangle AHB. Use the pythagorean theorem

(BH)^2 + (AH)^2 = (AB)^2

(y)^2 + (12-x)^2 = (9)^2

y^2 + 144-24x+x^2 = 81

-x^2+12x + 144-24x+x^2 = 81 ... replace y^2 with -x^2+12x

-x^2+12x + 144-24x+x^2-81 = 0

-12x + 63 = 0

-12x = -63

x = -63/(-12)

x = 5.25 <<-- answer in decimal form

x = 5 + 0.25

x = 5 + 1/4

x = 20/4 + 1/4

x = 21/4 <<-- answer as a fraction

3 0
3 years ago
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