For this case we have that by definition of power properties it is fulfilled that:

We must rewrite the following function:

Using the mentioned property we have:

Solving the operation within the parenthesis we have:

Thus, the correct option is option B
ANswer:
Option B
Answer:

Step-by-step explanation:
The distance d between a point (m , n ) and a line in the form
Ax + By + C = 0 , is calculated as
d = 
Here (m, n ) = (6, 2 ) and
6x - y = - 3 ( add 3 to both sides )
6x - y + 3 = 0 → A = 6, B = - 1, C = 3
d = 
= 
= 
=
× 
=
← cancel 37 on numerator/ denominator
= 
Answer:
Step-by-step explanation:
Simply substitute the x and y values into the equation, Infinity is a number that gets closer & closer to zero and the y-intercept is always 2.
Infinity is a number that gets closer & closer to zero and the y-intercept is always 2.
y=-2(2)(-infity)+2
y=2