He stop playing with his hamster at 4:06 because 3/5 of an hour is 36 minutes and 36 plus 3:30 is 4:06.
I'll do the first one to get you started
The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64
Compare that to y = ax^2+bx+c and we see that
a = 1
b = 16
c = 64
Use the values of 'a' and b to get the value of h as shown below
h = -b/(2a)
h = -16/(2*1)
h = -8
This is the x coordinate of the vertex.
Plug this x value into the original equation to find the corresponding y value of the vertex.
y = x^2+16x+64
y = (-8)^2 + 16(-8) + 64
y = 0
Since the y coordinate of the vertex is 0, this means k = 0.
The vertex is (h,k) = (-8, 0)
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So we found that a = 1, h = -8 and k = 0
Therefore,
f(x) = a(x-h)^2 + k
f(x) = 1(x-(-8))^2 + 0
f(x) = (x+8)^2
is the vertex form
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<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
when the time is between 0 and 15 minutes, the distance depends on the time on a relation: d =(1/10)t
when the time is between 15 and 40 minutes, the distance is independent of the time, it is fixed d = 1.5 miles
when the time is between 40 and 50 minutes, the distance depends on the time on the relation: d = 1.5 + (1/10)(t - 40)
Answer:
11
Step-by-step explanation:
1
1 + 2 = 3
3 + 2 = 5
5 + 2 = 7
7 + 2 = 9
9 + 2 = 11
