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OleMash [197]
2 years ago
12

Which of the following is considered to be the 3 dimensional figure

Mathematics
1 answer:
damaskus [11]2 years ago
8 0

Answer:

huhohou

Step-by-step explanation:

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Graph the system of equations.
Marat540 [252]
You can soustracte the first or the second one

and y cancel

x = 6

now you put 6 in x
you can take the first or the second one

6 - y = -2
6 - y = -2
y = -8
8 0
3 years ago
Round the following times to 1 decimal place 8.16
Mekhanik [1.2K]
The answer is 8.2 bc anything above a 5 goes up.
8.16 <<< a 6 is greater than 5. So the 1 goes up to a 2.
4 0
3 years ago
What is the distance from the point (a, −b, −4) to the origin?
laiz [17]

Answer:

  \sqrt{a^2+b^2+16}

Step-by-step explanation:

The distance (d) between two points in 3 dimensions is ...

  d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²)

Then the distance between (a, -b, -4) and (0, 0, 0) is ...

  d = √((a -0)² +(-b -0)² +(-4 -0)²)

  = √(a² +b² +16)

6 0
3 years ago
Please help ...........​
sammy [17]

Answer:

Angle B = 80°

see attachment......

7 0
3 years ago
A particle is moving along a projectile path where the initial height is 96 feet with an initial speed of 16 feet per second. Wh
leonid [27]

Answer:

The maximum height of the particle is 100 ft

A is correct

Step-by-step explanation:

A particle is moving along a projectile path where the initial height is 96 feet with an initial speed of 16 feet per second.

The standard equation of parabolic projectile.

h(t)=-16t^2+v_0t+h_0

where,

v_0=16\ ft/s

h_0=96\ ft

h(t)=-16t^2+16t+96

So, we get the parabolic equation of path.

The maximum value at vertex.

t=-\dfrac{b}{2a}

t=-\dfrac{16}{-32}=\dfrac{1}{2}

Maximum at t=0.5

h(0.5)=-16(0.5)^2+16(0.5)+96

h(0.5)=100

Hence, The maximum height of the particle is 100 ft

4 0
3 years ago
Read 2 more answers
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