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Gre4nikov [31]
4 years ago
12

Nineteen students were invited to michelle's party. Three more boys than girls were invited. How many boys were invited?

Mathematics
2 answers:
EleoNora [17]4 years ago
8 0
Eleven boys were invited and eight girls were invited.
11-8=3
bekas [8.4K]4 years ago
7 0
11 boys and 8 girls because you divide it in half the add 2 and subtract 1. That isn't the wy you are supposed to do it but it works and makes since in my head.
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What is the value of the expression shown below 10+(2x3)^2 divided by 4x (1/2)^3
stira [4]

Answer:

10 + (2 x 3)^2 / 4 x (1/2) ^3

First do the parentheses

2 x 3 = 6

1 / 2 = 0.5

We are left with

10 + 6^2 /4 x 0.5^3

Do exponents

6 x 6 = 36

0.5 x 0.5 x 0.5 = 0.125

10 + 36 / 4 x 0.125

Divide by 4 and multiply by 0.125

36 / 4 = 9

9 x 0.125 = 1.125

We are left with

10 + 1.125 = 11.125

The answer is 11.125

Step-by-step explanation:

7 0
3 years ago
Can you guys please help me with this. I really need these answers or i will get a 0 :( please make sure they're correct! <3
jek_recluse [69]
Well, both AMC are on the line I don’t exactly understand what the question is
6 0
3 years ago
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The length of a rectangle is 7 inches longer than it is wide. If the area is 20 square inches, what are the dimensions of the re
Arada [10]

Area of a rectangle is length x width.

Let the width = x

The length would be x +7. ( 7 inches longer than the width)

Area = 20

Set up the formula:

20 = x * x+7

Simplify the right side:

20 = x^2 + 7x

Subtract 29 from both sides:

X^2 + 7x -20 = 0

Solve using the quadratic equation

X = -b + sqrt(b^2 -4ac) / 2a

X = -7 + sqrt(7^2-4(1)(-20) / 2(1) (exact answer)

X = 2.178908 ( as a decimal)

The width is 2.178907 inches (round as needed)

The length would be 9.178907 inches ( round as needed.)

Depending on how you round, when you multiply them together you get approximately 20 square inches.

4 0
3 years ago
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Archy [21]

We can't find explicit values for x and y, since there is only one equation, but two variables.


The best we can do is solve for one variable with respect to the other:


Solve for x:


subtract 5y from both sides:


110-5y = 9x


divide both sides by 9:


\frac{110-5y}{9} = x


Solve for y:


subtract 9x from both sides:


110-9x = 5y


divide both sides by 5:


\frac{110-9x}{5} = y



5 0
3 years ago
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Studentka2010 [4]
This is uselful! Thanks: ))
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