First you collect the like term then variable one side coefficient one side and constant
Answer:
Cost of per session the average rate is $45.
Step-by-step explanation:
It is given that a gym membership with two personal training session cost $125, while gym membership with five personal training sessions cost $260.
It is required to find what is the cost per session.
Step 1 of 1
It is given that a gym membership with two personal training session cost $125, while gym membership with five personal training sessions cost $260.
To find the cost of per session calculate the average rate.
Now let $f(x)$ be the cost per session use the for the average rate of change, and the input value is the number of personal traings x.

Now substitute, $125 for
, 260 for
for
and 5 for
then,

Cost of per session the average rate is $45.
Answer:
<u><em>(x, y) -------> ( - x , y - 10 )</em></u>
Step-by-step explanation:
Titus is not correct.
There are two transformations will correctly prove FEDCBA ≅ F'E'D'C'B'A'
First transformation is Reflection over y-axis , then translation 10 units down.
The final formula is <em>( - x , y - 10 )</em>
Answer:
The probability that an athlete chosen is either a football player or a basketball player is 56%.
Step-by-step explanation:
Let the athletes which are Football player be 'A'
Let the athletes which are Basket ball player be 'B'
Given:
Football players (A) = 13%
Basketball players (B) = 52%
Both football and basket ball players = 9%
We need to find probability that an athlete chosen is either a football player or a basketball player.
Solution:
The probability that athlete is a football player = 
The probability that athlete is a basketball player = 
The probability that athlete is both basket ball player and football player = 
We have to find the probability that an athlete chosen is either a football player or a basketball player
.
Now we know that;

Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.
Can you take a better picture. That would help to answer the question.