Answer:
Please see attached image and all steps below for both parts
Step-by-step explanation:
Task 1
The following system of equations includes a linear equation and a quadratic one:

it can be solved by using substitution in the second equation of the variable "y" by the linear expression of the first equation:

and this product of two factors will e zero when either factor is zero, that is: when x = 0, or when x = 9 [to make zero the binomial(x - 9)]
There are two solutions: x = 0 and x = 9.
When we graph both expressions in the system, we see that the line intercepts the parabola at the points (0, 2) and (9, 11). See attached image.
Task 2
Part 1:
Let's pick 30 as a number larger than 25. 30 can be written as 40 - 10
So we can use:

to calculate its square.
Part 2:
let's choose a=9 and b=10 so we use:

Answer:
16-(-2)/ -6-(-4)= 18/-2= -9
Step-by-step explanation:
y2-y1/ x2-x1
U can see the answer in the picture below
Answer:
x= -5
Step-by-step explanation:
Add 5 to both sides
-3x -5+5 = 10 +5
-3x = 15
Divide both sides by -3.
-3x/-3= 15/-3
x= -5
45-15= 30-28= 2+18=20
Is that what the question was asking??