Answer:
12
Step-by-step explanation:
Let the two points be represented by (x1,y1) and (x2,y2).
Distance between the two points is given by the formula:
![\[\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B%28x2-x1%29%5E%7B2%7D%2B%28y2-y1%29%5E%7B2%7D%7D%5C%5D)
----------------- (1)
In this case x1=-2,y1=6,x2=-2,y2=18.
Substituting the relevant values in the formula (1),
distance = ![\[\sqrt{(-2-(-2))^{2}+(18-6)^{2}}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B%28-2-%28-2%29%29%5E%7B2%7D%2B%2818-6%29%5E%7B2%7D%7D%5C%5D)
= ![\[\sqrt{0^{2}+12^{2}}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B0%5E%7B2%7D%2B12%5E%7B2%7D%7D%5C%5D)
=12
Answer:
Wher is the graph below
Step-by-step explanation:
how can we answer it correctly?
Answer:
true
Step-by-step explanation:
-3x^2 + 2y^2 = 10
2y^2 = 10 + 3x^2
y^2 = 5 + 3/2x^2
distance between two points is given by
d = sqrt((x2 - x1)^2 + (y2 - y1)^2) = sqrt((x - 4)^2 + (y - 0)^2) = sqrt((x - 4)^2 + y^2) = sqrt((x - 4)^2 + 5 + 3/2x^2)
For d to be minimum (closest), dd/dx = 0
(2(x - 4) + 3x)/2sqrt((x - 4)^2 + 5 + 3/2x^2) = 0
2(x - 4) + 3x = 0
2x - 8 + 3x = 0
5x = 8
x = 8/5 = 1.6
y^2 = 5 + 3/2(1.6)^2 = 5 + 3/2(2.56) = 221/25
y = sqrt(221/25) = 2.97
Therefore, the required point is (1.6, 2.97)
If your solving for x, you need to isolate/get the variable "x" by itself in the inequality:
-24 ≤ 3x - 9 First add 9 on both sides
-24 + 9 ≤ 3x - 9 + 9
-15 ≤ 3x Then divide 3 on both sides to get "x" by itself
-5 ≤ x [or x ≥ -5 if you prefer "x" to be on the left side]
