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maxonik [38]
2 years ago
12

Expand -2/20 (1 - 2x + 2)

Mathematics
1 answer:
leonid [27]2 years ago
6 0

The expansion of the expression is \frac{4x - 6}{20}

<h3>How to expand the expression</h3>

Given the expression;

-2/20 (1 - 2x + 2)

= \frac{-2}{20} × (1 -2x +2 )

Open up the bracket by multiply with -2, we have

= \frac{-2 + 4x -4}{20}

Collect like terms in the numerator

= \frac{4x - 6}{20}

Thus, the expression of the expression is \frac{4x - 6}{20}

Learn more about algebraic expression here:

brainly.com/question/723406

#SPJ1

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43 rounded to the nearest tenth is 40 hope this helps! =3


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Convert 120 lbs to kilograms. (1 kg = 2.2 lbs)
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Answer:

54.4

Step-by-step explanation:

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Lila bought a green poster that measured 36 inches by 24 inches and a red poster that measured 12 inches by 18 inches. If the po
Alex777 [14]

Answer:

Total amount she spent on the posters = $43.2  +  $10.8  = $54

Step-by-step explanation:

Lila bought a green poster that measured 36 inches by 24 inches and a red poster that measured 12 inches by 18 inches. The posters cost per square inch is $0.05 .

To know how much she spend on the posters one have to convert the measured values of the posters to square inches(area).

Green poster  

area of rectangle = Lb

area of rectangle = 36 × 24

area of rectangle = 864 square inch

since 1 square inch = $0.05

864 square inch = ?

cross multiply

864 × 0.05 = $43.2

Red posters

area of rectangle = Lb

area of rectangle = 12 × 18

area of rectangle = 216  square inches

since 1 square inch = $0.05

864 square inch = ?

cross multiply

216 × 0.05 = $10.8

Total amount she spent on the posters = $43.2  +  $10.8  = $54

7 0
3 years ago
The first terms of an infinite geometric sequence, Un are 2, 6, 18, 54... The first terms of a second infinite geometric sequenc
gladu [14]

Answer:

r = 9 and m = 112

Step-by-step explanation:

\sum_{k=1}^{225}W_{k}=\sum_{k=0}^{m}4r^{k}

Write W in terms of U and V.

\sum_{k=1}^{225}(U_{k}+V_{k})=\sum_{k=0}^{m}4r^{k}\\\sum_{k=1}^{225}U_{k}+\sum_{k=1}^{225}V_{k}=\sum_{k=0}^{m}4r^{k}

Define U and V using geometric series formula.

\sum_{k=1}^{225}2(3)^{k-1}+\sum_{k=1}^{225}2(-3)^{k-1}=\sum_{k=0}^{m}4r^{k}

Use sum of geometric series formula.

2(\frac{1-(3)^{225}}{1-3})+2(\frac{1-(-3)^{225}}{1-(-3)})=4(\frac{1-(r)^{m+1}}{1-r})

Simplify.

-1(1-3^{225})+\frac{1+3^{225}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\-1+3^{225}+\frac{1}{2}+\frac{3^{225}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\-\frac{1}{2}+\frac{3(3^{225})}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\\frac{-1+3(3^{225})}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\\frac{-1+3^{226}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{-1+3^{226}}{8}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{1-3^{226}}{-8}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{1-9^{113}}{1-9}=4(\frac{1-(r)^{m+1}}{1-r})

Therefore, r = 9 and m = 112.

8 0
3 years ago
julius and olivia collect coins. julius has 338 coins in his collection. the number of coins olivia has is 57 less than double t
anygoal [31]
1) Julius and Olivia collect coins. {Qualitative statement}

2) Julius (J) has 338 coins in his collection. {Quantitative statement}

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3) The number of coins Olivia (V) has is 57 less than double the number of coins Julius has. {Quantitative statement}

V = 2*J - 57

V = 2*338 - 57

V = 619

------

Olivia has 619 coins.
7 0
4 years ago
Read 2 more answers
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