A:amount of money invested in the account with 3% simple interest
B: amount of money invested in the account with 4.5% simple interest
a+b=25000 ——>a=25000-b
0.03a+0.045b=900
30a+45b=900000
2a+3b=60000
2(25000-b)+3b=60000
50000-2b+3b=60000
B=10000
A=25000-10000=15000
4x+2(3-2x)=10, 4x+6-4x=10, x+6=10, x=4
1) use the distance formula to find that the radius (r) of the circle = 5
2) use the midpoint formula to find that the center of the circle (h,k) = (3, 0)
3) Now use the formula of a circle and input the (h,k) and r to create:
(x - 3)² + (y - 0)² = 5² → (x - 3)² + y² = 25
4) input the "x" value given in the question (x = 0) and solve for "y":
(0 - 3)² + y² = 25 → 9 + y² = 25 → y² = 16 → y = +/- 4
Since the question states that "b" must be positive, you can disregard the -4.
Answer: b = 4
Answer:
Answer Below
Step-by-step explanation:
Triangle #1
To solve this answer we need to multiply then <em>divide by 2</em>
x 
÷ 
12
Triangle #2
Now we do the same thing!
x
÷
12
Rectangle #1
<em>Now we solve for the rectangle!</em>
x 
48
Now we add all these together!
<em>The answer is D. 72 Square Units</em>
The zeroes of the polynomial functions are as follows:
- For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
- For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
- For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1
<h3>What are the zeroes of a polynomial?</h3>
The zeroes of a polynomial are the vales of the variable which makes the value of the polynomial to be zero.
The polynomials are given as follows:
f(x) = 2x(x - 3)(2 - x)
f(x) = 2(x - 3)²(x + 3)(x + 1)
f(x) = x³(x + 2)(x - 1)
For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1
In conclusion, the zeroes of a polynomial will make the value of the polynomial function to be zero.
Learn more about polynomials at: brainly.com/question/2833285
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