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Marat540 [252]
3 years ago
13

How does this simplify?

Mathematics
1 answer:
jekas [21]3 years ago
6 0
\bf \cfrac{-6\pm\sqrt{40}}{2}\implies \cfrac{-6\pm\sqrt{2^2\cdot 10}}{2}\implies \cfrac{-6\pm 2\sqrt{10}}{2}
\\\\\\
-3\pm\sqrt{10}
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Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $30 and same-day tickets cost
Andre45 [30]

The number of advance tickets sold is 25 and same day tickets sold is 30.

Data Given;

  • Advance Ticket = $30
  • Same-day Ticket = $25
  • Total Ticket = $60
  • Total Cost of Ticket = $1625

<h3>System of Equations</h3>

Let the number of advance ticket be represented by x

Let the number of same-day ticket be represented by y

x + y = 60\\&#10;30x + 25y = 1625

From the system of equations above, we can easily pick any to start our calculation.

Using equation (i),

x + y = 60

x = 60 - y ...equation(iii)

Put equation (iii) into equation (ii)

30x + 25y = 1625\\&#10;x = 60 - y\\&#10;30(60 - y) + 25y = 1625\\&#10;1800 - 30y + 25y = 1625\\&#10;1800 -5y = 1625\\&#10;5y = 1800 - 1625\\&#10;5y = 175\\&#10;5y/5 = 175/5\\&#10;y = 35

Put the value of y into equation (i)

x+y = 60\\&#10;x + 35 = 60\\&#10;x = 60 - 35\\&#10;x = 25

From the calculation above, the number of advance tickets sold is 25 and same-day tickets is 30.

Learn more on system of equations here;

brainly.com/question/13729904

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cricket20 [7]

Answer:

No solution because it is minus 9

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Divide 2/8 by 9/18 . Input your answer as a reduced fraction.\
Katen [24]

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8 0
2 years ago
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In order to slove the following system of equations by addition, which of the following could you do before adding the equations
Vladimir [108]

Answer:

  B. use multipliers -3 and 2

Step-by-step explanation:

If you're solving the system by "addition," multiplying the equations by the chosen numbers needs to result in opposite coefficients for one of the variables.

<h3>Effect of answer choices</h3>

A. The system becomes ...

  • 12x -6y = 21
  • 12x -12y = 60

No variable has opposite coefficients.

__

B. The system becomes ...

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The y-variable has opposite coefficients. This is a good choice.

__

C. The system becomes ...

  • 12x -6y = 21
  • 6x -6y = 30

No variable has opposite coefficients.

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D. The system becomes ...

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No variable has opposite coefficients.

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<em>Additional comment</em>

The simplest "no brainer" solution is to use the coefficients of one of the variables, negating one of them. Multiply each equation by the opposite equation's coefficient. Here, the y-coefficients are -2 and -3, and the multipliers of answer choice B are -3 and 2, consistent with this advice. (The sign of 2 was changed.)

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I need a little help with my math problem.
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