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2 years ago

Suppose that the relation H is defined as follows.

Mathematics

1 answer:

Norma-Jean [14]2 years ago

6 0

Answer:

Domain = {-8, 2}
Range = {-2, -1, 7}

Step-by-step explanation:

The domain is the set of x values, and the range is the set of y values.

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What is the approximate volume of one refraction cup? What’s its formula ?

Marizza181 [45]

Answer:

Volume = 0.1696 L

The formula is Area of base of refraction cup × Depth of the refraction cup

Step-by-step explanation:

The dimensions of a refraction cup are;

Diameter = 120 mm

Depth = 30 mm

Therefore, volume of the refraction cup = Area of base × Depth

Volume of the refraction cup = (π×120²/4)/2 × 30 = 169646.003 mm³

1 L = 1000000 mm³

Therefore, 169646.003 mm³ = 169646.003/1000000 m³ = 0.1696 L

The formula is Area of base of refraction cup × Depth of the refraction cup.

6 0

3 years ago

Your class sells a box of oranges to raise $500 for a field trip.You earn $6.25 for each box of oranges sold.Write and solve an

emmainna [20.7K]

To do this, find the slope, y-intercept, and your goal.

Your goal is 500.
Your slope is 6.25 per orange.
Your y-intercept is 0 (you don't start out with anything.)

So, the inequality is $500 \leq 6.25x$ .

8 0

3 years ago

Read 2 more answers

On Texas Avenue between University Drive and George Bush Drive, accidents occur according to a Poisson process at a rate of thre

Zarrin [17]

Answer:

(a) The probability is 0.6514

(b) The probability is 0.7769

Step-by-step explanation:

If the number of accidents occur according to a poisson process, the probability that x accidents occurs on a given day is:

$P(x)=\frac{e^{-at}*(at)^{x} }{x!}$

Where a is the mean number of accidents per day and t is the number of days.

So, for part (a), a is equal to 3/7 and t is equal to 1 day, because there is a rate of 3 accidents every 7 days.

Then, the probability that a given day has no accidents is calculated as:

$P(x)=\frac{e^{-3/7}*(3/7)^{x}}{x!}$

$P(0)=\frac{e^{-3/7}*(3/7)^{0}}{0!}=0.6514$

On the other hand the probability that February has at least one accident with a personal injury is calculated as:

P(x≥1)=1 - P(0)

Where P(0) is calculated as:

$P(x)=\frac{e^{-at}*(at)^{x} }{x!}$

Where a is equivalent to (3/7)(1/8) because that is the mean number of accidents with personal injury per day, and t is equal to 28 because 4 weeks has 28 days, so:

$P(x)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{x}}{x!}$