Suppose that the relation H is defined as follows.
1 answer:
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The answer to the system of equation is (2,0)
6x - 3y = 12 --->> 3y = 6x - 12 -->> y = 2 x -4
y = 2x - 4
y = x - 2
In this case we subtract y = x - 2 from y = 2x - 4
So, it would be
y = 2x - 4
-(y = x - 2) --->> -y = -x +2
y = 2x - 4
-y = -x + 2
---------------
0 = x - 2
Now we add 2 to both sides to isolate x
So, x = 2
Now we replace x for two in both equations.
6(2) - 3y = 12
12 - 3y = 12 (I'm distributing)
-3y = 0
3y = 0
y = 0
Now the other equation
y = 2 -2
y = 0
So, the answer is (2,0)
I hope this helps.
YOU'RE WELCOME :D
6x - 3y = 12 --->> 3y = 6x - 12 -->> y = 2 x -4
y = 2x - 4
y = x - 2
In this case we subtract y = x - 2 from y = 2x - 4
So, it would be
y = 2x - 4
-(y = x - 2) --->> -y = -x +2
y = 2x - 4
-y = -x + 2
---------------
0 = x - 2
Now we add 2 to both sides to isolate x
So, x = 2
Now we replace x for two in both equations.
6(2) - 3y = 12
12 - 3y = 12 (I'm distributing)
-3y = 0
3y = 0
y = 0
Now the other equation
y = 2 -2
y = 0
So, the answer is (2,0)
I hope this helps.
YOU'RE WELCOME :D