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mina [271]
3 years ago
8

How to solve -2(v-2)=-3-2v i need it step by step

Mathematics
2 answers:
Lisa [10]3 years ago
5 0

Answer:

No solution

Step-by-step explanation:

Given: -2(v-2)=-3-2v

Distribute -2 at the left side of the equal sign:

-2v+4=-3-2v

Put all like terms in one side:

-2v+2v=-3-4

Combine all like terms:

0=-12

Answer: No solution

Goryan [66]3 years ago
3 0

Answer:O0

Step-by-step explanation:

2*(v-2)-(-3-2*v)=0

STEP

1

:

Equation at the end of step 1

(0 - 2 • (v - 2)) - (-2v - 3) = 0

STEP

2

:

Equation at the end of step 2

7 = 0

STEP

3

:

Equations which are never true:

3.1 Solve : 7 = 0

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Which could be the area of one face of the rectangular prism? Select three options.
antiseptic1488 [7]

Answer:

44cm^2

Step-by-step explanation:

We work with area for rectangles using the face of the longer length first as this is the awkward length the perpendicular side to the easy calculation of the square and sits perpendicular to the square.

We choose the longer length and plug in and choose one of the two calculation answers.

11 x 4 = 44

11 x 6 = 66

We see the answer is 44cm^2, so we choose this one.

8 0
3 years ago
A laptop computer is purchased for 3100. Each year, its value is 75% of its value the year before. After how many years will the
Stella [2.4K]

Answer:7 to 9? Years

Step-by-step explanation: I’m not sure but if you got a couple trys try to do it.

6 0
3 years ago
Read 2 more answers
I need help asap....................
docker41 [41]

Based on the given points, the point that is located on the y-axis is (0,7).

<h3>Which point is on the y axis?</h3>

The point that is on the y-axis should have a coordinate such that x is equal to 0.

This leads to the point being on the y-axis because the nonzero coordinate of the y axis would then have to be placed on the same axis.

The only point with a 0 coordinate is (0, 7) so this is the point that is located on the y-axis.

Find out more on points on the y-axis at brainly.com/question/4656315

#SPJ1

7 0
2 years ago
PLEASE HELP ME ASAP! Please show your work.
Marysya12 [62]
Its 18....................................


6 0
3 years ago
PLZ HELP!!! Use limits to evaluate the integral.
Marrrta [24]

Split up the interval [0, 2] into <em>n</em> equally spaced subintervals:

\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]

Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,

r_i=\dfrac{2i}n

where 1\le i\le n. Each interval has length \Delta x_i=\frac{2-0}n=\frac2n.

At these sampling points, the function takes on values of

f(r_i)=7{r_i}^3=7\left(\dfrac{2i}n\right)^3=\dfrac{56i^3}{n^3}

We approximate the integral with the Riemann sum:

\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{112}n\sum_{i=1}^ni^3

Recall that

\displaystyle\sum_{i=1}^ni^3=\frac{n^2(n+1)^2}4

so that the sum reduces to

\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{28n^2(n+1)^2}{n^4}

Take the limit as <em>n</em> approaches infinity, and the Riemann sum converges to the value of the integral:

\displaystyle\int_0^27x^3\,\mathrm dx=\lim_{n\to\infty}\frac{28n^2(n+1)^2}{n^4}=\boxed{28}

Just to check:

\displaystyle\int_0^27x^3\,\mathrm dx=\frac{7x^4}4\bigg|_0^2=\frac{7\cdot2^4}4=28

4 0
3 years ago
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