Find the surface area of the composite figure

In 2008 election there was 28 blue states and 22 red states express the red and blue states as fractions in lowest terms of the

Basile [38]

Let's start with the blue states. Out of 50 states, 28 of them were blue.
Therefore, the fraction would be 28/50. Let's reduce it.
28/50=14/25 --> these are the lowest terms for this fraction
Use a calculator to find the decimal solution --> 14/25= .56

Now, let's do the red states. Out of the 50 states, 22 of them were blue.
22/50=11/25 --> lowest terms
Use a calculator --> 11/25= .43

8 0

4 years ago

Victor's Video Arcade pays its employees $7.95 per hour for weekday hours and $9.25 per hour for weekend hours. How much will an

Ivan

Answer:

i can't understand ur question

3 0

3 years ago

Suppose 850 tickets were sold for a game for a total of $1100. If adult tickets cost $1.50 and children tickets cost $1.00, how

Nesterboy [21]

500 adult tickets and 350 children tickets.

Check :
500A($1.5)=$750
350C($1)=$350

$750 + $350 = $1100 AND 500 + 350 = 850 tickets

8 0

4 years ago

1. Ramon spends 2/5 of his monthly income on rent, 1/5 of his monthly income on utilities, and 3/4 of the amount remaining on fo

hichkok12 [17]

If x is how much his income is then 2/5x+1/5x= 3/5x for rent and utilities. x-3/5x=2/5x leftover. 3/4×2/5x=3/10x for food. 3/5x+3/10x=9/10x spent on rent, utilities, and food and rec. He saves the rest which is x-9/10x= 1/10x so if 1/10x=193.50
x= $1,935 for his income

7 0

3 years ago

During the first 13 weeks of the television season, the Saturday evening 8:00 p.m. to 9:00 p.m. audience proportions were record

SpyIntel [72]

Part 1: Do not reject H0. There has not been a significant change in the viewing audience proportions.(The above conclusion holds as the p-value is greater than the significance level of 0.05)

Part 2:

H0:

Ha:

Part 3: The test statistic is given as 3.0081.

Part 4: The p-value is given as 0.39037

Step-by-step explanation:

As per the data

Part 2

H0:

Ha:

Part 3

As per the sample is of 300 homes, the expected values are given as

ABC=p(ABC)*300=0.30*300=90

CBS=p(CBS)*300=0.27*300=81

NBC=p(NBC)*300=0.26*300=78

IND=p(IND)*300=0.17*300=51

Now the values actually are given as

ABC=94

CBS=71

NBC=88

IND=47

So the test static is given as

So the test statistic is given as 3.0081.

Part 4

Now the degree of freedoms are given as 4-1=3

and chi square is given as 3.0081 so for α = 0.05 , the p-value is given as 0.39037

Part 1.

As the value of p in part 4 is greater than the value of α = 0.05, thus Do not reject H0. There has not been a significant change in the viewing audience proportions.(The above conclusion holds as the p-value is greater than the significance level of 0.05)

4 0

3 years ago