Timed please help added picture

12. Find the value of x. (11x - 15 (5x - 13°

anyanavicka [17]

Answer:

x = 13

Step-by-step explanation:

(11x - 15) + (5x - 13) =180

16x -28 = 180

16x = 208

x = 13

4 0

3 years ago

(5x^2-8x+1)+(2x^2-6x+7) simplify

harina [27]

Step-by-step explanation:

all work is shown/pictured

4 0

3 years ago

Hurry plz! Will vote Brainly or whatever and will reward all point I can.

Naily [24]

Answer: 0.27

You can mark me brainliest on the other question you know

Step-by-step explanation:

3 0

4 years ago

At the start of the school year, students in Mr. Pi’s class were asked the

kupik [55]

Answer:

No, there is not enough information to determine how many students were absent that particular morning.

Explanation:

The probability of randomly selecting a student who answered the question “yes” is the number of students that responded yes divided by the number of students present. Thus, it was:

21/30 = 7/10

The probability of randomly selecting a student who answered the question “no” is the number of students who answered "no" divided by the number of students present. Thus, it was:

9/30 = 3/10

On one particular morning later in the year, the probability of randomly selecting a student who had answered the question “yes” was 3/4

The equivalent ratios to 3/4 will tell you the possible combinations of students that answered yes and students present on that particular morning.

For instance: 3/4 = 6/8

6/8 would mean that there were 6 students that answered yes and 8 total students on that particular morning.

Since more than half of class was present, the total number of students was greater than 15. Then, you must find a ratio with a denominator greater than 15 (and less than 30).

The other equivalent ratios to 3/4 are: 9/12, 12/16, 15/20, 18/24, 21/28, 24/32, ...

That means that the only possibilities with more than 15 and less than 30 present students are 12/16, 15/20, 18/24, and 21/28.

The total number of absents might have been:

30 - 28 = 2
30 - 24 = 6
30 - 20 = 10
30 - 16 = 14

Since at least one of the students who had answered “yes” was absent and at least one of the students who had answered “no” was absent, all the above possibilities are valid: there is not enough information to determine how many students were absent that particular morning; they could be 2, 6, 10, or 14.

7 0

3 years ago

Solve 3/8 = 6w-7/2w+14

Studentka2010 [4]

(PLEASE GIVE THIS BRAINLIEST)Multiply the numbers
3
8
=
6

−
1
⋅
7
2

+
1
4
3
8
=
6
w
−
1
⋅
7
2
w
+
14
83=6w−1⋅27w+14
3
8
=
6

−
7
2

+
1
4
Combine multiplied terms into a single fraction
3
8
=
6

−
7
2

+
1
4
3
8
=
6
w
−
7
2
w
+
14
83=6w−27w+14
3
8
=
6

+
−
7

2
+
1
4
3
8
=
6
w
+
−
7
w
2
+
14
83=6w+2−7w+14
3
Find common denominator
3
8
=
6

+
−
7

2
+
1
4
3
8
=
6
w
+
−
7
w
2
+
14
83=6w+2−7w+14
3
8
=
2
⋅
6

2
+
−
7

2
+
2
⋅
1
4
2
3
8
=
2
⋅
6
w
2
+
−
7
w
2
+
2
⋅
14
2
83=22⋅6w+2−7w+22⋅14
4
Combine fractions with common denominator
3
8
=
2
⋅
6

2
+
−
7

2
+
2
⋅
1
4
2
3
8
=
2
⋅
6
w
2
+
−
7
w
2
+
2
⋅
14
2
83=22⋅6w+2−7w+22⋅14
3
8
=
2
⋅
6

−
7

+
2
⋅
1
4
2
3
8
=
2
⋅
6
w
−
7
w
+
2
⋅
14
2
83=22⋅6w−7w+2⋅14
5
Multiply the numbers
3
8
=
2
⋅
6

−
7

+
2
⋅
1
4
2
3
8
=
2
⋅
6
w
−
7
w
+
2
⋅
14
2
83=22⋅6w−7w+2⋅14
3
8
=
1
2

−
7

+
2
⋅
1
4
2
3
8
=
12
w
−
7
w
+
2
⋅
14
2
83=212w−7w+2⋅14
6
Multiply the numbers
3
8
=
1
2

−
7

+
2
⋅
1
4
2
3
8
=
12
w
−
7
w
+
2
⋅
14
2
83=212w−7w+2⋅14
3
8
=
1
2

−
7

+
2
8
2
3
8
=
12
w
−
7
w
+
28
2
83=212w−7w+28
7
Combine like terms
3
8
=
1
2

−
7

+
2
8
2
3
8
=
12
w
−
7
w
+
28
2
83=212w−7w+28
3
8
=
5

+
2
8
2
3
8
=
5
w
+
28
2
83=25w+28
8
Multiply all terms by the same value to eliminate fraction denominators
3
8
=
5

+
2
8
2
3
8
=
5
w
+
28
2
83=25w+28
2
⋅
3
8
=
2
(
5

+
2
8
2
)
2
⋅
3
8
=
2
(
5
w
+
28
2
)
2⋅83=2(25w+28)
9
Cancel multiplied terms that are in the denominator
2
⋅
3
8
=
2
(
5

+
2
8
2
)
2
⋅
3
8
=
2
(
5
w
+
28
2
)
2⋅83=2(25w+28)
2
⋅
3
8
=
5

+
2
8
2
⋅
3
8
=
5
w
+
28
2⋅83=5w+28
10
Multiply the numbers
2
⋅
3
8
=
5

+
2
8
2
⋅
3
8
=
5
w
+
28
2⋅83=5w+28
3
4
=
5

+
2
8
3
4
=
5
w
+
28
43=5w+28
11
Subtract
2
8
28
28
from both sides of the equation
3
4
=
5

+
2
8
3
4
=
5
w
+
28
43=5w+28
3
4
−
2
8
=
5

+
2
8
−
2
8
3
4
−
28
=
5
w
+
28
−
28
43−28=5w+28−28
12
Simplify
Subtract the numbers
Subtract the numbers
−
1
0
9
4
=
5

−
109
4
=
5
w
−4109=5w
13
Divide both sides of the equation by the same term
−
1
0
9
4
=
5

−
109
4
=
5
w
−4109=5w
−
1
0
9
4
5
=
5

5
−
109
4
5
=
5
w
5
5−4109=55w
14
Simplify
Divide the numbers
Cancel terms that are in both the numerator and denominator
Move the variable to the left

=
−
1
0
9
2
0
w
=
−
109
20
w=−20109

7 0

3 years ago

Timed please help added picture​

Timed please help added picture