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natima [27]
2 years ago
7

Please help mee, sketch the graph please (50 points will give brainliest!!!)

Mathematics
1 answer:
Jlenok [28]2 years ago
6 0

Values are given below as pairs (x,y) where x coordinate is x values in box and y coordinate is y values on box

  • (-5,9)
  • (-4,4)
  • (-2,0)
  • (0,4)
  • (1,9)

Graph attached

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3 years ago
Please help i need this answer in 5 min
strojnjashka [21]

Answer:6

Step-by-step explanation:

using BIDMAS: Brackets,Indices,division,multiplication,addition,subtraction.

1) Firstly you do the problem in the brackets. (-19 - -20) two negatives next to each other make a plus(+) meaning (-19 - -20) = (-19+20) which = 1

2) Next Step is to do the multiplication section. Since we got 1 in place instead of (-19 - -20) we multiply -3 by 1 which = -3.

3) Now the equation we have is 11 + -8 - -3. In BIDMAS both addition and subtraction are equal therefore we can do it in any order. 11 + -8 is the same as 11 - 8 = 3

4) The problem we have now is 3 - -3, like we said before two negatives next to each other make an addition sign(+) so 3 - -3 = 3+3 = 6, therefore getting the answer 6.

Thank you for reading,please let me notify me if I've missed anything out!

6 0
2 years ago
Read 2 more answers
Evaluate the expression, thank you!
sergeinik [125]

Answer:

(0.7- -5x-0.2)= (0.7-1)= -1.7

-1.7/0.3 = -5.66666666667

7 0
3 years ago
Helppp meeee with thisss for a thanksss
harkovskaia [24]
<h3>Answer: 45 degrees</h3>

The purple arc is 315 degrees. The remaining bit (angle b) must add to 315 to get 360 degrees, which is a full rotation.

315+b = 360

b = 360-315

b = 45

4 0
3 years ago
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Three out of seven students in the cafeteria line are chosen to answer survey questions. How many different combinations of thre
Hatshy [7]

Answer:

35 possible combinations would be there.

Step-by-step explanation:

We have total of seven students we have to choose three out of those seven

^{n}C_r=\frac{n!}{r!\cdot (n-r)!}

n is the total possibilities n =7 in the given case

And r is the chosen ones

Hence, r=3 in the given case.

Substituting the values of n and r in the formula we get

^{7}C_3

\frac{7!}{3!(7-3)!}

\frac{7!}{3!\cdot 4!}

Using n!=n(n-1)----1

\frac{7\cdot 6\cdot 5\cdot 4!}{3\cdot 2\cdot 1\cdot 4!}

Cancel the  common factor we get

35  possible combinations would be there.

8 0
3 years ago
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