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LenaWriter [7]
3 years ago
14

In ABC, if mA is six less than 7 times x, mB is five less than three times x, and mC is five less than four times x, find x and

the measure of each angle
Mathematics
1 answer:
alexgriva [62]3 years ago
4 0

Answer:

a=92  b=37  c=51

Step-by-step explanation:

a= 7x-6

b=3x-5

c=4x-5

7x-6+3x-5+4x-5=180

14x-16=180

14x=196

x=14

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Alchen [17]

Answer:

answer is 3.144

Step-by-step explanation:

6 0
3 years ago
Given: BAD = CAD. Find the perimeter of ABC.
11111nata11111 [884]

Answer:

34 units

Step-by-step explanation:

Since the triangles are equal, the bottom length of triangle CAD will be the same as the bottom length of BAD. This means that the total length of the bottom of triangle ABC is 6 (3 + 3).

Next, you need to find the length of AC and again, since they're the same triangle, AB will be the same as AC, 14.

The three side lengths of the triangle will be 6, 14, and 14, so the perimeter is

6 + 14 + 14 = 34 units

4 0
3 years ago
What is the median of the data set? {17, 40, 23, 44, 44, 30} Enter your answer in the box.
beks73 [17]
To find the median of the data set, we must first order them from lowest to highest in increasing order. Let's rearrange them in that way:

{17, 23, 30, 40, 44, 44}

Then we begin by crossing one off from each side, until we get to the middle. However, we see that our middle here is both 30 and 40.

What we do in a case like this is add up the two numbers and divide by 2 (essentially find the mean of the two middlemost numbers). Let's do that now:

30+40=70

\frac{70}{2}=35

So now we know that the median of the set of data is 35.
8 0
3 years ago
The probabilty that a student owns a car is 0.65 the porbability that a student owns a compuer is 0.82 the probability that a st
DanielleElmas [232]

Question:  The probability that s student owns a car is 0.65, and the probability that a student owns a computer is 0.82.

a. If the probability that a student owns both is 0.55, what is the probability that a randomly selected student owns a car or computer?

b. What is the probability that a randomly selected student does not own a car or computer?

Answer:

(a) 0.92

(b) 0.08

Step-by-step explanation:

(a)

Applying

Pr(A or B) = Pr(A) + Pr(B) – Pr(A and B)................. Equation 1

Where A represent Car, B represent Computer.

From the question,

Pr(A) = 0.65, Pr(B) = 0.82, Pr(A and B) = 0.55

Substitute these values into equation 1

Pr(A or B) = 0.65+0.82-0.55

Pr(A or B) = 1.47-0.55

Pr(A or B) = 0.92.

Hence the probability that a student selected randomly owns a house or a car is 0.92

(b)

Applying

Pr(A or B) = 1 – Pr(not-A and not-B)

Pr(not-A and not-B) = 1-Pr(A or B) ..................... Equation 2

Given: Pr(A or B)  = 0.92

Substitute these value into equation 2

Pr(not-A and not-B) = 1-0.92

Pr(not-A and not-B) = 0.08

Hence the probability that a student selected randomly does not own a car or a computer is 0.08

8 0
3 years ago
I need help with this
Sloan [31]
That equals 27 hope this helps
3 0
3 years ago
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