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3 years ago

What is the value of X?

Mathematics

1 answer:

Leviafan [203]3 years ago

4 0

Answer:

x=20

Step-by-step explanation:

First, find LJ

Angle L = 60 (180 - 30 - 90)

The cosine of an angle is equal to the ratio of the adjacent side to the hypotenuse.

cos(L)=adj/hyp

cos(60)=LJ/40√2

LJ = cos(60)*40√2

LJ = 20√2

Now you can use LJ to find x. You also know the value of each angle, 45

x=20√2⋅cos(45)

x=20

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Represent the geometric series using the explicit formula.

Dennis_Churaev [7]

The correct answer is:

b.) f(n) = 3 • (-2)^(n-1)

Further explanation:

Given sequence is:

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It is denoted by r.

So,

$Here,\\a_1=3\\a_2=-6\\a_3=12\\a_4=-24\\r=\frac{a_2}{a_1}=\frac{-6}{3}=-2\\\frac{a_3}{a_2}=\frac{12}{-6}=-2$

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$a_n=a_1r^{n-1}\\Here\\a_n\ is\ the\ nth\ term\\a_1\ is\ the\ first\ term\\and\\r\ is\ common\ ratio$

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$a_n=3.(-2)^{n-1}\\f(n)=3.(-2)^{n-1}$

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b.) f(n) = 3 • (-2)^(n-1)

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We have the following three conclusions about the <em>piecewise</em> function evaluated at x = 14.75:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
$\lim_{t \to 14.75^{+}} f(t) = 10$ .
$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

<h3>How to determinate the limit in a piecewise function</h3>

In a <em>piecewise</em> function, the limit for a given value exists when the two <em>lateral</em> limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.

According to the definition of <em>lateral</em> limit and by observing carefully the figure, we have the following conclusions:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
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$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

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