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Fittoniya [83]
2 years ago
13

In the following exercises, multiply the binomials. Use any method. 242. (y + 7)(y + 4)

Mathematics
2 answers:
Hatshy [7]2 years ago
8 0

Answer:

Hence the expression $(y+7)(y+4)=y^{2}+11 y+28$

Step-by-step explanation:

- The given expression is (y+7)(y+4).

- We have to multiply the given expression.

- Multiply the (y+7) by 4 , multiply the (y+7) by y then add like terms.

\begin{array}{r}y+7 \\\underline {\times \quad y+28} \\4 y+28 \\\underline {y^{2}+7 y }\\y^{2}+11 y+28\end{array}

baherus [9]2 years ago
6 0
The answer: y^2+11y+28
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If p - 5q = 4qr,<br> p<br> find the value of p when<br> q = 4 and r = -1.
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p - 5q = 4qr where

q = 4 and r = -1 by applying these value

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p - 20 = -16

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4 0
2 years ago
6. On a bank account of $2,500, how much yearly interest will be paid if the rate is3.4%?
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Multiply the amount in the account by the interest rate:

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3 years ago
What's the number in between numbers -10 and 70?
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80

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7 0
3 years ago
Read 2 more answers
When fishing off the shores of Florida, a spotted seatrout must be between 10 and 30 inches long before it can be kept; otherwis
Mademuasel [1]

Answer:

There is a 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

The lengths of the spotted seatrout that are caught, are normally distributed with a mean of 22 inches, and a standard deviation of 4 inches, so \mu = 22, \sigma = 4.

What is the probability that a fisherman catches a spotted seatrout within the legal limits?

They must be between 10 and 30 inches.

So, this is the pvalue of the Z score of X = 30 subtracted by the pvalue of the Z score of X = 10

X = 30

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 22}{4}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 10

Z = \frac{X - \mu}{\sigma}

Z = \frac{10 - 22}{4}

Z = -3

Z = -3 has a pvalue of 0.00135.

This means that there is a 0.9772-0.00135 = 0.97585 = 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

3 0
3 years ago
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