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3 years ago

Please help this is my final

Mathematics

1 answer:

alexdok [17]3 years ago

6 0

The answer would be

Slope is -7

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What is the solution to the system of equations? O (-4,1) O (-2, 1) O (1.4) O (1,-2)

Tcecarenko [31]

Answer:

$(1,-2)$

Step-by-step explanation:

Given

The attached graph

Required

Determine the solution

The solution here is the intersection points of the two lines. From the attachment, both lines meet

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Hence, the solution is: $(1,-2)$

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3 years ago

Simplify the following expression to simplest form using only positive exponents.

Novosadov [1.4K]

Answer:

$\frac{x^{6} }{4y^{10} }$

Step-by-step explanation:

THIS is the answer if the equation looks like this. $(32x^{-15} y^{25} )^{-2.5}$

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3 years ago

A spinner has 10 equally sized sections, 5 of which are gray and 5 of which are blue. The spinner is spun twice. What is the pro

zhenek [66]

Answer:

$P(Gray\ and\ Blue) = \frac{1}{4}$

Step-by-step explanation:

Given

$Sections = 10$

$n(Gray) = 5$

$n(Blue) = 5$

Required

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Using probability formula;

$P(Gray\ and\ Blue) = P(Gray) * P(Blue)$

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$P(Gray) = \frac{n(Gray)}{Sections}$

$P(Gray) = \frac{5}{10}$

$P(Gray) = \frac{1}{2}$

Calculating P(Gray)

$P(Blue) = \frac{n(Blue)}{Sections}$

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$P(Blue) = \frac{1}{2}$

Substitute these values on the given formula

$P(Gray\ and\ Blue) = P(Gray) * P(Blue)$

$P(Gray\ and\ Blue) = \frac{1}{2} * \frac{1}{2}$

$P(Gray\ and\ Blue) = \frac{1}{4}$

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3 years ago

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Sergio039 [100]

Answer:

can you please show attachments?

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