Answer:
The probability of assembling the product between 7 to 9 minutes is 0.50.
Step-by-step explanation:
Let <em>X</em> = assembling time for a product.
Since the random variable is defined for time interval the variable <em>X</em> is continuously distributed.
It is provided that the random variable <em>X</em> is Uniformly distributed with parameters <em>a</em> = 6 minutes and <em>b</em> = 10 minutes.
The probability density function of a continuous Uniform distribution is:
Compute the probability of assembling the product between 7 to 9 minutes as follows:
Thus, the probability of assembling the product between 7 to 9 minutes is 0.50.
Answer:
Take a look at the 'proof' below
Step-by-step explanation:
The graph of the function g(x) is similar to that of the function f(t). The local minimum, local maximum, absolute minimum, maximum etc... of 'x' is always the closest x-intercept of the graph of f(t).
Let's check if this statement is right. The two local minimum(s) of the function f(t) occurs at x = 2, and x = 6. The two local maximum(s) occur at 1/4 and 4. As you can see the maximum / minimum of the function g(x) is always an x-intercept, x = 3, x = 7.
For part (b) the absolute maximum value of the function f(t), is 8. The closest x-intercept is 9, which is our solution.
Answer:
3 (5x+2y = 0)
2 (2x – 3y = -19)
Step-by-step explanation:
5x+2y=0 (1)
2x-3y=-19 (2)
To eliminate y from the first two equation when applying the linear combination method
We will multiply y Equation (1) and (2) with 3 and 2 respectively so that the coefficients of y in the two equations +6 and -6 respectively
3(5x+2y=0)
2(2x-3y=-19)
We have,
15x+6y=0 (3)
4x-6y= -38 (4)
Add Equation (3) and (4)
19x=-38
x= -2
Substitute x= -2 into (1)
5x+2y=0
5(-2)+2y=0
-10+2y=0
-10= -2y
y=-10/-2
=5
y=5, x=-2
Answer:
Step-by-step explanation:
Given
See attachment for complete question
First, we calculate the water pipe length (AC):
The cost of laying across water is twice (2 times) laying on land.
So, the total cost (C) is:
Differentiate
To find the most economical cost, we simply minimize C' by equating C' to 0
Cross multiply
Take square of both sides
Collect like terms
Solve for
Solve for x
Rationalize: