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adoni [48]
3 years ago
15

Jordana is putting a fence around a garden that is shaped like a half circle and a rectangle. A rectangle with length 28 feet an

d width 14 feet. A semicircle with diameter 14 feet is on top of the rectangle. How much fencing will Jordana need? Use StartFraction 22 over 7 EndFraction for Pi. 64 ft 86 ft 92 ft 114 ft
Mathematics
2 answers:
solmaris [256]3 years ago
5 0

Answer:

The answer is 92 on Edginuity

Step-by-step explanation:

Xelga [282]3 years ago
4 0

Answer:

It is C. 92

Step-by-step explanation:

I did the test on edgenuit y

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Three more than twice some number
olya-2409 [2.1K]

Answer:

2x + 3

Step-by-step explanation:

Let's call the number x

twice a number is 2 times the number, or in this case 2x

3 more than 2x is 2x + 3

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DochEvi [55]
The answer should be 60.
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What is 20-17.16 because im confused
goblinko [34]

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2.84

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20.00 - 17.16 : If you think of it with zeros it might help

2.84 when solved

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What is 1 million times 4358
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What is 1 million times 4358

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To decrease the impact on the environment, factory chimneys must be high enough to allow pollutants to dissipate over a larger a
Komok [63]

Answer:

The probability hat the sample mean height for the 40 chimneys is greater than 102 meters is 0.1469.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the height of chimneys in factories.

The mean height is, <em>μ</em> = 100 meters.

The standard deviation of heights is, <em>σ</em> = 12 meters.

It is provided that a random sample of <em>n</em> = 40 chimney heights is obtained.

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

Since the sample selected is quite large, i.e. <em>n</em> = 40 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean heights of chimneys.

\bar X\sim N(\mu_{\bar x},\ \sigma^{2}_{\bar x})

Compute the probability hat the sample mean height for the 40 chimneys is greater than 102 meters as follows:

P(\bar X>102)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}})>\frac{102-100}{12/\sqrt{40}})

                    =P(Z>1.05)\\=1-P(Z

*Use a <em>z</em>-table fr the probability.

Thus, the probability hat the sample mean height for the 40 chimneys is greater than 102 meters is 0.1469.

8 0
3 years ago
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