Answer:
(x+8,y-6)
Step-by-step explanation:
it's the number of values that x and y differ
Answer:
y=-2x+5
Step-by-step explanation:
y=-2x+5
Since they are vertical angles, they equal each other. Therefor the equation would be: 30x-29 = 20x+21
10x = 50
X = 5
After, you plug whatever x is back into the other equations.
20(5)+21 = 121 and 30(5)-29 = 121
Answer:
Step-by-step explanation:
Given function is,


This function is not defined at "x(x - 2) = 0"
Therefore, for the values of x = 0 and 2, given function is not defined.
Vertical asymptote → x = 2 [Denominator = 0]
For Horizontal asymptote → ![[\frac{2x^2}{-4x^2} =-\frac{1}{2}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B2x%5E2%7D%7B-4x%5E2%7D%20%3D-%5Cfrac%7B1%7D%7B2%7D%5D)
Therefore, horizontal asymptote → y =
x-intercept,
For f(x) = 0,
Numerator of the function = 0
2x² + 6x = 0
2x(x + 3) = 0
x = -3
Therefore, x - intercept → (-3, 0)
For y-intercept,
x = 0
f(0) = 0
Therefore, graph has no y-intercept.
For holes on the graph,
Since, function is not defined at x = 0,
f(x) = 
f(0) = 
= 
Therefore, hole on the graph → 