More data can be applied to the frequency distribution table. You can measure the "midpoint" (or "class mark") of each class as: Midpoint = Lower class limit + Upper class limit 2 . . The proportion of the data that falls in that class is the "relative frequency" of each class.
Answer:
each bag weights 1,500 grams
Step-by-step explanation:
there are 1000 grams in a kilogram
6 times 1000 is 6000
6000 divided by 4 is 1500
Answer:
z<2
Step-by-step explanation:
-2(z + 5) + 20 > 6
Subtract 20 from each side
-2(z + 5) + 20 -20 > 6-20
-2(z + 5) > -14
Divide each side by -2 remembering to flip the inequality
-2/ -2(z + 5) < -14/-2
z+5 < 7
Subtract 5 from each side
z+5-5 < 7-5
z<2
Given a fragpole which makes a right angle with the point of observation with the angle of elevation as 50°.
Let x be the height of the flagpole, then

Therefore, the <span>equation that could be used to find the height of the flagpole is
</span><span>x/5 = sin 50</span>
We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12
we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13
sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13
sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant
therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12
the answer ispoint (-5,12)
see the attached figure