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2 years ago

For what values of the variable are the following expressions defined?

Mathematics

1 answer:

Rom4ik [11]2 years ago

3 0

Answer:

The Expression will be defined if the denominator is not equal to 0 since any number divided by 0 is undefined.
Therfore our main priority here is to check the denominator only because it's the only part that can make the expression undefined
the expression will be defined for all real numbers (a) BUT 3+a must not equal to 0 therfore (a) can be all real numbers but must never be equal to -3

Step-by-step explanation:

$a \: is \: an \: element \: of \: all \: real \: numbers \: but \: not \: not \: equal \: to \: -3$
HOPE THIS HELPS!

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At a certain college, the probability that a student attends full-time is 0.320 and the probability that the student attends par

IRISSAK [1]

Sorry i really don't know the answer.......................................................

3 0

3 years ago

Which statement is true about f(x)-2/3lx+4l-6?

slamgirl [31]

1) Taking in account that the function is f(x)= -(2/3) |x+4|-6, I enclose a file with the graph.

That helps you to conclude:

a) The graph of f(x) has a vertex on (-4, -6)

b) When you multiply a function times 2/3 it is vertically compressed which is equivalent to horizontally streched.

c) The graph of f(x) opens downward

d) The domain of f(x) is all the real values (the absolute function accepts any value of x either positive or negative)

Answer: the graph of f(x) is horizontally stretched.

7 0

3 years ago

Read 2 more answers

The Robotics Manufacturing Company operates an equipment repair business where emergency jobs arrive randomly at the rate of thr

cluponka [151]

Answer:

The correct answer is:

$\lambda=0.375 \ jobs \ per \ hour$
$\mu=0.5 \ jobs \ per \ hour$

Step-by-step explanation:

The given values are:

Service time varies,

Repair time = 2 hours

Standard deviation = 1.5 hours

Robotics uses per hour cost,

= $35

Company's cost per hour,

= $28

(a)

⇒ Arrival rate = Jobs per hours

then,

= $\frac{8 \ hours}{3 \ jobs}$

= $2.666 \ hours \ per \ job$

The jobs per hour will be:

⇒ $\lambda=\frac{1}{2.666}$

$=0.375$

(b)

⇒ Service rate = jobs per hour

then,

μ = $\frac{1 \ repair \ job}{2 \ hours}$

= $0.5 \ jobs$

7 0

3 years ago

After how many seconds is the height 68 feet? When the equation is h=-16t2+64t+8

Rudiy27

<span>68=-16t2+64t+8
16t2-64t+60=0

4t2-16t+15=0
(2t-5)(2t-3)=0
t=5/2 or 3/2
The object is at 68 feet after 3/2 secs, and returns to 68 feet after another second..</span>

5 0

3 years ago

A red car is driving along the road in the direction of the police car and is 130 feet up the road from the location of the poli

pishuonlain [190]

Complete question:

A police car is located 50 feet to the side of a straight road. A red car is driving along the road in the direction of the police car and is 130 feet up the road from the location of the police car. The police radar reads that the distance between the police car and the red car is decreasing at a rate of 75 feet per second. How fast is the red car actually traveling along the road.

Answer:

The red car is traveling along the road at 80.356 ft/s

Step-by-step explanation:

Given

Police car is 50 feet side off the road

Red car is 130 feet up the road

Distance between them is decreasing at the rate of 75 feet per sec

Let x be how far the police is off the road.

Let y be how far the red car is up the road.

Let h be the distance between the police and the red car.

This forms a right triangle so we can use the Pythagorean theorem, to solve for h

h² = x² + y²

h² = 50² + 130²

h² = 19400

h = √19400

h = 139.284 ft

Again;

Let dx/dt be how fast the police is traveling toward the road.

Let dy/dt be how fast the red car is traveling along the road.

Let dh/dt be how fast the distance between the police and the car is decreasing.

Recall that, h² = x² + y² (now differentiate with respect to time, t)

2h(dh/dt) = 2x(dx/dt) + 2y(dy/dt)

divide through by 2

h(dh/dt) = x(dx/dt) + y(dy/dt)

since the police car is not, dx/dt = 0

and dy/dt is the how fast is the red car actually traveling along the road

139.284(75) = 50(0) + 130(dy/dt)

10446.3 = 0 + 130(dy/dt)

dy/dt = 10446.3 / 130

dy/dt = 80.356 ft/s

Therefore, the red car is traveling along the road at 80.356 ft/s

6 0

3 years ago