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Anestetic [448]
2 years ago
6

URGENT HELPPP !!!!!! Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!

Mathematics
1 answer:
GaryK [48]2 years ago
3 0

Answer:

(8,-3)

Step-by-step explanation:

I just added 1 to the x value and added 2 to the y value because that was the difference between point A and the midpoint of the segment.

Hope this helps!

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(x +y)(x-y), ifx= -3, y=-5
Rufina [12.5K]

Answer:

-16

Step-by-step explanation:

(-3 + (-5))(-3 - (-5))

(-3 - 5)(-3 + 5)

(-8)*2

<u>-16</u>

5 0
3 years ago
Read 2 more answers
Which ordered pair is a solution to the system of equations?
elixir [45]
I believe it would be (b) (-2,1)
4 0
3 years ago
Read 2 more answers
Kent worked in the housewares section of a department store. This year he set a record high for vacuum sales with 567 vacuums so
Mashcka [7]
It is a 5% increase from last year
5 0
3 years ago
What is the area of a circle with a diameter of 16?
Oksana_A [137]

If the diameter is 16, then the radius is 8.

A=(pi) r^2

8*8=64

64*3.14159265359=201.06

201.06 is your answer.

-TheOneandOnly003


4 0
3 years ago
Find a equation of a line that is perpendicular to y=-4x+3 and passes through the point (4,-1).
Marina86 [1]

Given:

The given equation is:

y=-4x+3

A line is perpendicular to the given line and passes through the point (4,-1).

To find:

The equation of required line.

Solution:

The slope intercept form of a line is:

y=mx+b

Where, m is slope and b is y-intercept.

We have,

y=-4x+3

Here, the slope of the line is -4 and the y-intercept is 3.

Let the slope of required line be m.

We know that the product of slopes of two perpendicular lines is -1. So,

m\times (-4)=-1

m=\dfrac{-1}{-4}

m=\dfrac{1}{4}

The slope of required line is m=\dfrac{1}{4} and it passes through the point (4,-1). So, the equation of the line is:

y-(-1)=\dfrac{1}{4}(x-4)

y+1=\dfrac{1}{4}(x)-\dfrac{4}{4}

y=\dfrac{1}{4}x-1-1

y=\dfrac{1}{4}x-2

Therefore, the equation of the required line is y=\dfrac{1}{4}x-2.

5 0
2 years ago
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