Answer:
e. reject the null hypothesis the p value is less than 0.05. therefore the difference is significant.
Step-by-step explanation:
given that after comparing response times between the audio and picture portions of the MIT test, the t-test resulted in a t-value of 2.97.
test statistic t = 2.97
Sample size n =250
Critical value of t at 95% is 1.96
We find that test statistic absolute value is greater than 1.96
So p value would be less than 0.05
This implies that null hypothesis stands in the rejected region.
So reject null hypothesis would be correct conclusion. Sample size cannot be said to be small as more than 30 itself is a good sample size.
e. reject the null hypothesis the p value is less than 0.05. therefore the difference is significant.
F(x)=5*2
the f(x) stands for a normal X like any other algebraic equation. so all it is, is 5 times 2, which is 10.
so,
f(x)=5*2
f(x)=10<span />
So these are basically isolating the variables.
The first equation is 3g + 5 =17.
In order to isolate the variable, we would have to get g by itself, that means 5 would have to go. In order to do this, we would do the opposite. Since it is positive 5 we would add negative 5, in order for it to disappear. This works because a positive 5 and negative 5 cancel each other out. Whatever you do to one side of the equation you have to do to the other, since we subtract 5 on one side we have to subtract 5 on the other. Therefore we would do 17-5.
Now we have 3g=12
We know that 3g is basically 3 multiplied by g. The opposite of multiplication is division.Therefore we would divide by 3 on both sides.
The answer to the first question would be g= 4.
And if you want to check if your answer is correct you plug the value in.
So
3(4) + 5 =17
Step-by-step explanation:
hi Maya how are you
I wasn't using this app so I didn't replied
and sorry for rejecting ur request in ff
I'll give my another I'd if u want to play
Answer:
Step-by-step explanation:
arithmetic sequence formula: 
where 
is the first term and 
is the common difference
Given:
⇒ 
⇒ 
Given:
⇒ 
⇒ 
Rearrange the first equation to make the subject:
a = 32 - 9d
Now substitute into the second equation and solve for
(32 - 9d) + 11d = 106
⇒ 32 + 2d = 106
⇒ 2d = 106 - 32 = 74
⇒ d = 74 ÷ 2 = 37
Substitute found value of into the first equation and solve for :
a + (9 x 37) = 32
a + 333 = 32
a = 32 - 333 = -301
Therefore, the equation is:
