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NeTakaya
3 years ago
10

Which systems of equations intersect at point A in this graph?

Mathematics
1 answer:
abruzzese [7]3 years ago
3 0

Answer:

The point of intersection of the system of equations is:

(x, y) =  (-2, 1)

The correct system of equations intersect at point A in this graph will be:

\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}

Thus, the second option is correct.

Step-by-step explanation:

Given the point

  • A (-2, 1)

Let us check the system of equations to determine whether it intersect at point A in this graph.

Given the system of equations

\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}

Arrange equation variable for elimination

\begin{bmatrix}y-4x=9\\ y+3x=-5\end{bmatrix}

so

y+3x=-5

-

\underline{y-4x=9}

7x=-14

so the system of equations becomes

\begin{bmatrix}y-4x=9\\ 7x=-14\end{bmatrix}

Solve 7x = -14 for x

7x=-14

Divide both sides by 7

\frac{7x}{7}=\frac{-14}{7}

Simplify

x = -2

For y - 4x = 9 plug in x = 2

y-4\left(-2\right)=9

y+4\cdot \:2=9

y+8=9

Subtract 8 from both sides

y+8-8=9-8

Simplify

y = 1

Thus, the solution to the system of equations is:

(x, y) = (-2, 1)

From the attached graph, it is also clear that the system of equations intersects at point x = -2, and y = 1.

In other words, the point of intersection of the system of equations is:

(x, y) =  (-2, 1)

Therefore, the correct system of equations intersect at point A in this graph will be:

\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}

Thus, the second option is correct.

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) All human blood can be typed as one of O, A, B, or AB. The distribution of the type varies a bit with race. For African-Americ
ivann1987 [24]

Answer:

The correct option is 1 - [(0.8)¹⁰+10*0.2*(0.8)⁹]= 0.6242

Step-by-step explanation:

Hello!

Given the distribution of probabilities for blood types for African-Americans:

O: 0.4

A: 0.2

B: 0.32

AB: 0.08

A random sample of 10 African-American is chosen, what is the probability that 2 or more of them have Type A blood?

Let X represent "Number of African-Americans with Type A blood in a sample of 10.

Then you have two possible outcomes,

"Success" the person selected has Type A blood, with an associated probability p= 0.2

"Failure" the selected person doesn't have Type A blood, with an associated probability q= 0.8

(You can calculate it as "1-p" or adding all associated probabilities of the remaining blood types: 0.4+0.32+0.08)

Considering, that there is a fixed number of trials n=10, with only two possible outcomes: success and failure. Each experimental unit is independent of the rest and the probability of success remains constant p=0.2, you can say that this variable has a Binomial distribution:

X~Bi(n;p)

You can symbolize the asked probability as:

P(X≥2)

This expression includes the probabilities: X=2, X=3, X=4, X=5, X=6, X=7, X=8, X=9, X=10

And it's equal to

1 - P(X<2)

Where only the probabilities of X=0 and X=1 are included.

There are two ways of calculating this probability:

1) Using the formula:

P(X)= \frac{n!}{(n-X)!X!} *p^{x} * q^{n-x}

With this formula, you can calculate the point probability for each value of X=x₀ ∀ x₀=1, 2, 3, 4, 5, 6, 7, 8, 9, 10

So to reach the asked probability you can:

a) Calculate all probabilities included in the expression and add them:

P(X≥2)= P(X=2) + P(X=3) + P(X=4) + P(X=5) + P(X=6) + P(X=7) + P(X=8) + P(X=9) + X=10

b) Use the complement rule and calculate only two probabilities:

1 - P(X<2)= 1 - [P(X=0)+P(X=1)]

2) Using the tables of the binomial distribution.

These tables have the cumulative probabilities listed for n: P(X≤x₀)

Using the number of trials, the probability of success, and the expected value of X you can directly attain the corresponding cumulative probability without making any calculations.

>Since you are allowed to use the complement rule I'll show you how to calculate the probability using the formula:

P(X≥2) = 1 - P(X<2)= 1 - [P(X=0)+P(X=1)] ⇒

P(X=0)= \frac{10!}{(10-)0!0!} *0.2^{0} * 0.8^{10-0}= 0.1074

P(X=1)= \frac{10!}{(10-1)!1!} *0.2^{1} * 0.8^{10-1}= 0.2684

⇒ 1 - (0.1074+0.2684)= 0.6242

*-*

Using the table:

P(X≥2) = 1 - P(X<2)= 1 - P(X≤1)

You look in the corresponding table of n=10 p=0.2 for P(X≤1)= 0.3758

1 - P(X≤1)= 1 - 0.3758= 0.6242

*-*

Full text in attachment.

I hope it helps!

8 0
3 years ago
37 pumpkins each weighs 48 ounces
KiRa [710]
37 * 48 = 3 * (c  - 140 )+ 2 *(c  - 140 ) + ( c - 140 ) =>
37 * 48 = 6 * ( c - 140 ) =>
37 * 48 / 6 = c - 140 =>
37 * 8 = c - 140 =>
296 = c - 140 => 
c = 296 + 140 =>
c = 436 ounces.
5 0
3 years ago
Elijah can spend up to $23 on groceries. She wants to buy 3 pounds of tomatoes, 4 pounds of oranges, and x pounds of lean ground
Colt1911 [192]

Answer: 2 pounds

Step-by-step explanation:

Hope this helps!!! ; )

7 0
3 years ago
Dividing monomials please help and quick!!​
Snezhnost [94]

Answer:

answer is of left to right

16x^14/(36x^2)=4x^12/9

(3^3)×(x^5)×y÷4

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7 0
3 years ago
Solve this system of equations without graphing and show your reasoning
Drupady [299]

Answer:

x = 1/5

y = 6

Step-by-step explanation:

System:

{5x + y = 7

{20x + 2 = y

First equation:

5x + y = 7 -> y = -5x + 7

Plug into second equation:

20x + 2 = -5x + 7

Subtract 2 from both sides:

20x = -5x + 5

Add 5x to both sides:

25x = 5

Divde both sides by 25:

x = 5/25 -> 1/5

~~~~~~~~~~~~~~~~~~~~~~~~~~~`

Come back to the first equation:

5x + y = 7

Plus in our x:

5(1/5) + y = 7

Multiply:

1 + y = 7

Subtract 1 from both sides:

y = 6

Hope this helps, have a nice day! :D

7 0
2 years ago
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