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Leya [2.2K]
3 years ago
10

What are the factors of 3x2 + 13x + 4?

Mathematics
2 answers:
DiKsa [7]3 years ago
6 0

Now, ASSUMING that you mean 3x^2+13x+4 for factors, your answer will be

(3x+1) (x+4)

If you meant 3x2+13x+4 then your answer will be

3x^2+17 ( ^ meaning squared)

padilas [110]3 years ago
5 0
S<span>tep-1 : Multiply the coefficient of the first term by the constant </span><span> <span> 3</span> • 4 = 12</span> 

<span>Step-2 : Find two factors of </span> 12 <span> whose sum equals the coefficient of the middle term, which is  </span><span> 13 </span><span>.
</span><span><span>

-12   +   -1   =   -13</span><span>     
-6   +   -2   =   -8</span><span>     
-4   +   -3   =   -7</span><span>     
-3   +   -4   =   -7</span><span>     
-2   +   -6   =   -8</span><span>     
-1   +   -12   = -13</span><span>     
1   +   12   =   13 </span></span>
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Helpp worth 20 points!!<br>write the equation of the line below<br><br>​
Anit [1.1K]

Answer:

y = -x -2

Step-by-step explanation:

7 0
2 years ago
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Which function is a shrink of the exponential growth function shown on the graph?
fgiga [73]
The exponential function shown in the graph is 3^x, so (1/2)3^x is a shrink of it.

Selection B is appropriate.
3 0
3 years ago
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An analyst from an energy research institute in California wishes to precisely estimate a 99% confidence interval of the average
Lena [83]

Answer:

190

Step-by-step explanation:

Data provided in the question:

Confidence level = 99%

Therefore,

α = 1% = 0.01

[ from standard normal table ]

z-value for z_{\frac{\alpha}{2}}= z_{\frac{0.01}{2}}= = 2.58

Margin of error, E = $0.06

Standard deviation, σ = $0.32

Now,

n = (\frac{z_{0.005}\sigma}{E})^2

Here,

n is the sample size (or the minimum number of gas stations  )

on substituting the respective values, we get

= (\frac{z_{0.005}\sigma}{E})^2

= (\frac{2.58\times0.32}{0.06})^2

= 13.76²

= 189.3376 ≈ 190

Hence,

minimum number of gas stations that she should include in her sample is 190

5 0
3 years ago
A study sampled 350 upperclassmen (Group 1) and 250 underclassmen (Group 2) at high schools around the city of Portland. The stu
iVinArrow [24]

Answer:

-0.061 < P_1 -P_2< 0.025

Step-by-step explanation:

Give data:

n_1 = 350

n_2 =250

x_1 = 23

x_2 = 21

\hat{P} 1 = \frac{x_1}{n_1} = \frac{23}{350} = 0.066

\hat{P} 2 = \frac{x_2}{n_2} = \frac{21}{250} = 0.084

for 95% confidence interval

\alpha = 1 - 0.95 = 0.05 and \alpha/2 = 0.025

z_{\alpha/2} = 1.96  from standard z- table

confidence interval for P_1  and P_2 is

\hat{P} 1 - \hat{P} 2 \pm z_{\alpja/2} \sqrt{\frac{\hat{P} 1(1-\hat{P} 1)}{n_1} +\frac{\hat{P} 2(1-\hat{P} 2)}{n_2}}

(0.066 - 0.084) \pm 1.96 \sqrt{\frac{0.066(1-0.066)}{350} +\frac{0.084(1-0.084)}{250}}

-0.018 \pm 0.043

confidence interval is

-0.018 - 0.043 < P_1 -P_2

-0.061 < P_1 -P_2< 0.025

7 0
3 years ago
Order the fractions from least to greatest. A)− 8/3 , − 5/2 , − 7/ 4 , − 3/ 5 B) − 3/ 5 , − 5/2 , − 7/4 , − 8/3 C) − 8/3 , − 5/2
Olenka [21]

Answer:

A)− 8/3 , − 5/2 , − 7/ 4 , − 3/ 5

Step-by-step explanation:

8 0
3 years ago
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