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serg [7]
2 years ago
11

5-4-3-2

Mathematics
2 answers:
weeeeeb [17]2 years ago
5 0

Answer:

1st option

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

here (h, k ) = (- 2, 1 ) and r = 3 , then

(x - (- 2) )² + (y - 1)² = 3² , that is

(x + 2)² + (y - 1)² = 9 ← expand factors using FOIL

x² + 4x + 4 + y² - 2y + 1 = 9

x² + 4x + y² - 2y + 5 = 9 ( subtract 9 from both sides )

x² + 4x + y² - 2y - 4 = 0 , that is

x² + y² + 4x - 2y - 4 = 0 ← in general form

Ludmilka [50]2 years ago
3 0

Answer:

\textsf{1)} \quad x^2+y^2+4x-2y-4=0

Step-by-step explanation:

<u>Equation of a circle</u>

(x-a)^2+(y-b)^2=r^2

where:

  • (a, b) is the center
  • r is the radius

From inspection of the graph:

  • center of the circle = (-2, 1)
  • radius of the circle = 3

Substitute the found values into the formula:

\implies (x-(-2)^2+(y-1)^2=3^2

\implies (x+2)^2+(y-1)^2=9

Expand and simplify:

\implies (x+2)^2+(y-1)^2=9

\implies x^2+4x+4+y^2-2y+1=9

\implies x^2+y^2+4x-2y+5=9

\implies x^2+y^2+4x-2y-4=0

Learn more here:

brainly.com/question/27783217

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