so this is how i was taught the inverse function. f(x) is basicly the same thing as saying y
so y=x over x+3
you switch the top x with y so it turns in to x=y over x+3
the problem should tell you what x equals so substitute x with the number it equals and then solve
here is an example f(x)=x over x+3 and x=14
x=y over x+3
14=y over 14+3
the inverse inverse function would probably be just solve the equation so just substitute the number they give you for x in for x
Answer:
Step-by-step explanation: 3root5x^2 + 25x - 10root5 = 0
3xroot5 + 25x - 10root5 = 0 [ root x^2 = x]
28x root5 = 10 root5 [ -10root5 turns to 10 root5 when transferred to RHS]
28x root 5/root5 =10
28x=10
x = 10/28
x = 0.35
Hope it helped u,
pls mark as the brainliest
^v^
Answer:
![60cm^{2}](https://tex.z-dn.net/?f=60cm%5E%7B2%7D)
Step-by-step explanation:
so first we need to find the height so by splitting the isosceles triangle into two right-angled triangles and then applying Pythagoras' Theorem to one of them.
![h^{2} =13^{2} -5^{2}](https://tex.z-dn.net/?f=h%5E%7B2%7D%20%3D13%5E%7B2%7D%20-5%5E%7B2%7D)
![h^{2} =169-25](https://tex.z-dn.net/?f=h%5E%7B2%7D%20%3D169-25)
![h^{2} =144](https://tex.z-dn.net/?f=h%5E%7B2%7D%20%3D144)
![h=\sqrt{144}](https://tex.z-dn.net/?f=h%3D%5Csqrt%7B144%7D)
![h=12](https://tex.z-dn.net/?f=h%3D12)
We now know the height of the triangle and can use this to go back and find the area of the isosceles triangle.
area of triangle =
x base x height
area of triangle =
x 10 x 12
area of triangle = 60
It will be the second option i believe
Answer:
x=10,−10
simple, it could be negative OR positive :D