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m_a_m_a [10]
3 years ago
11

The product of three positive integers is 300. If one of them is 5, what is the

Mathematics
1 answer:
Elan Coil [88]3 years ago
4 0

Answer and Step-by-step explanation:

So, we are told that 3 positive integers multiply to be 300, and that one of the integers is 5.

First, we divide 300 by 5.

The result is 60.

Now, we take different (reasonable) numbers that add to 16:

10 and 6

12 and 4

We can see here that 10 and 6 are the integers because they add up to 16 and multiplies to 60.

#teamtrees #WAP (Water And Plant)

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Answer:

A college student took 4 courses last semester. His final grades, along with the credits each class is worth, are as follow: A (3), B (4), C (2), and D (3). The grading system assigns quality points as follows: A: 4; B: 3; C: 2; D: 1; and F: 0. Find the student’s GPA for this semester. Round your answer to the nearest thousandth.

another way is

This is a weighted average question. You are going to "weight" each course by the number of credits it is worth and then divide by the total number of credits. In other words, you are going to multiply each grade (A=4, B=3) by the number of credits attached to that grade. This will ensure that the courses that have more credits count more in the overall average. Then you are going to divide by the total number of credits to get the overall GPA.

So,

(3*4 + 4*3 + 2 *2 + 3*1)/(3+4+2+3) = GPA

Step-by-step explanation:

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Find the radius of a circle that has a circumference of 16 .
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2.55

Step-by-step explanation:

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What is the answer for y=3x+6
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Step-by-step explanation:

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2 years ago
How do you solve X/2-5=10
Afina-wow [57]

Answer: x2-5=10  

Two solutions were found :

                  x = ± √15 = ± 3.8730

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2"   was replaced by   "x^2".  

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    x^2-5-(10)=0  

Step by step solution :

Step  1  :

Trying to factor as a Difference of Squares :

1.1      Factoring:  x2-15  

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 15 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares.

Equation at the end of step  1  :

 x2 - 15  = 0  

Step  2  :

Solving a Single Variable Equation :

2.1      Solve  :    x2-15 = 0  

Add  15  to both sides of the equation :  

                     x2 = 15

 

When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:  

                     x  =  ± √ 15  

The equation has two real solutions  

These solutions are  x = ± √15 = ± 3.8730  

 

Two solutions were found :

                  x = ± √15 = ± 3.8730

Step-by-step explanation:

5 0
2 years ago
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