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mihalych1998 [28]
3 years ago
13

Find a numerical value of one trigonometric function of x for cscx = sinx tanx + cosx

Mathematics
1 answer:
Alex787 [66]3 years ago
6 0

Answer:

Step-by-step explanation:

we have

cscx = sinx tanx + cosx\\\\\frac{1}{sinx}=sinx.\frac{sinx}{cosx} +cosx\\\\\frac{1}{sinx}.sinx.cosx= sinx.\frac{sinx}{cosx}.sinx.cosx+cosx.sinx.cosx\\  cosx= (sinx)^{3} +sinx.(cosx)^{2} \\cosx= sinx[(sinx)^{2}+(cosx)^{2})\\  cosx=sinx.1\\cosx=sinx\\tanx=1\\x=\frac{\pi}{4} +k\pi,k-integer.

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is it possible draw a right triangle with and obtuse angle? if so draw it in the box if not write impossible. is it possible guy
Ipatiy [6.2K]
It is not possible. Since one of the angles has to be a right angle, the other two angles would have to add to 90. Therefore, neither of these angles can be more than 90 degrees. 

Hope this helps
3 0
3 years ago
State whether each sequence is arithmetic and justify your answer. If the sequence is arithmetic, write a recursive and an expli
nasty-shy [4]

Answer:

Part A

f(n)=52-12(n-1)

f(n)=\left\{\begin{matrix}52\: \:if \: \:n=1 & \\f(n+1)+12& if\: n\geq 2 \end{matrix}\right.

Part B

(2,4,8,16,32)\: \: Geometric Sequence

Part C

1/4,3/4,5/4,7/4,9/4

g(n)=\frac{1}{4}+\frac{2}{4}(n-1)\\f(n)=\left\{\begin{matrix}1/4if \: \:n=1 & \\ f(n+1)+2/4& if\: n\geq 2 \end{matrix}\right

Part D:

h(n)=1.1+0.4(n-1)\\h(n)=\left\{\begin{matrix}1.1 & if\:n=1 \\ h(n+1)+0.4 & if\:n\geq 2\end{matrix}\right

Step-by-step explanation:

By definition, an Arithmetic Sequence holds the same difference between each following number.

Part A

(52,40, 28, 16)\\52-40=12\\40-28=12\\28-16=12\\d=12

<u>Explicit Formula</u>

To write an explicit formula is to write it as function.

f(n)=52-12(n-1)

<u>Recursive Formula</u>

To write it as recursive formula, is to write it as recurrence given to some restrictions:

f(n)=\left\{\begin{matrix}52\: \:if \: \:n=1 & \\f(n+1)+12& if\: n\geq 2 \end{matrix}\right.

Part B

(2,4,8,16,32)\: \:

Geometric Sequence, since 2*2=4 8*2=16 and 16*2=32 and 8+2=10 8+16=24

Part C

(\frac{1}{4},\frac{3}{4},\frac{5}{4},\frac{7}{4},\frac{9}{4})\\\

Arithmetic Sequence, difference

d=\frac{2}{4}

<u>Explicit Formula:</u>

g(n)=\frac{1}{4}+\frac{2}{4}(n-1)

<u>Recursive Formula</u>

g(n)=\left\{\begin{matrix}\frac{1}{4} &if\:n=1 \\ g(n+1)+\frac{2}{4} &if\: n\geq 2\end{matrix}\right.

Part D

(1.1,1.5,1.9,2.3,2.7) Arithmetic Sequence, difference d=0.4

<u>Explicit formula</u>

h(n)=1.1+0.4(n-1)\\

<u>Recursive Formula</u>

h(n)=\left\{\begin{matrix}1.1 &if\:n=1 \\ h(n+1)+0.4 &if\: n\geq 2\end{matrix}\right.

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If a fair die is rolled 6 times, what is the probability, to the nearest thousandth, of
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Answer: 0.000

Step-by-step explanation:

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We are given that triangle AOB

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Answer:

I think the answer is -4

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3 years ago
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