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mihalych1998 [28]
2 years ago
13

Find a numerical value of one trigonometric function of x for cscx = sinx tanx + cosx

Mathematics
1 answer:
Alex787 [66]2 years ago
6 0

Answer:

Step-by-step explanation:

we have

cscx = sinx tanx + cosx\\\\\frac{1}{sinx}=sinx.\frac{sinx}{cosx} +cosx\\\\\frac{1}{sinx}.sinx.cosx= sinx.\frac{sinx}{cosx}.sinx.cosx+cosx.sinx.cosx\\  cosx= (sinx)^{3} +sinx.(cosx)^{2} \\cosx= sinx[(sinx)^{2}+(cosx)^{2})\\  cosx=sinx.1\\cosx=sinx\\tanx=1\\x=\frac{\pi}{4} +k\pi,k-integer.

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Step-by-step explanation:

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Answer:

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