Question

Factorise completely qn: 12axy + 8bxy + 4xy

Answer 1

Answer:

4xy(3a+2b+1)

Step-by-step explanation:

1)  Find the Greatest Common Factor (GCF).

1 - What is the largest number that divides evenly into 12axy, 8bxy and 4xy?

It is 4.

2 -  What is the highest degree of $a$  that divides evenly into 12axy, 8bxy and 4xy?

It is 1, since a is not in every term.

3 -  What is the highest degree of $x$ that divides evenly into 12axy, 8bxy and 4xy?

It is x.

4 - What is the highest degree of $y$  that divides evenly into  12axy, 8bxy and 4xy?

It is y.

5 -  What is the highest degree of $b$ that divides evenly into 12axy, 8bxy and 4xy?

It is 1, since $b$ is not in every term.

6 - Multiplying the results above,

GCF = 4xy

2)  Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

$4xy(\frac{12axy}{4xy} +\frac{8bxy}{4xy} +\frac{4xy}{4xy} )$

3) Simplify each term in parentheses.

$4xy(3a+2b+1)$

Answer 2

Answer:

Step-by-step explanation: