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Rus_ich [418]
1 year ago
11

With the aid of an illustration from a well labelled diagram, explain a cross over experimental design using a scenario with thr

ee treatment
Mathematics
1 answer:
RideAnS [48]1 year ago
4 0

A crossover design is a reiterated assessments design in which each experimental unit (patient) receives various treatments at different time periods, i.e., the patients switch from one therapy to another during the trial.

<h3>What is the advantage of a crossover design?</h3>

The crossover design has the benefit of each subject acting as his or her own control, and it requires a lesser number of patients than parallel-group trials.

There are various drawbacks. For example, crossover designs often last longer than parallel-group research.

Learn more about experiments at;
brainly.com/question/16286146
#SPJ1

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Nesterboy [21]

Answer in the attachment.

3 0
3 years ago
In a trapezoid with bases of lengths a and b, a line parallel to the bases is drawn through the intersection point of the diagon
mote1985 [20]

if we name that part x, then we can say

1/x = 1/a + 1/b

3 0
3 years ago
At what point on the curve x^2 + y^2 = 9 is the tangent line vertical?
Gemiola [76]

x² + y² = 9 is the equation of a circle with center (0, 0) and radius 3.

This puts the vertices at (-3, 0), (3, 0), (0, -3), and (0, 3).

When is the tangent line vertical? <em>when it passes through the x-axis.</em>

Answer: (-3, 0), (3, 0)

7 0
3 years ago
Type the correct answer in the box. Use a comma to separate the x- and y-coordinates of each point. The coordinates of the point
MAVERICK [17]

Answer:

On a unit circle, the point that corresponds to an angle of 0^{\circ} is at position (1, \, 0).

The point that corresponds to an angle of 90^{\circ} is at position (0, \, 1).

Step-by-step explanation:

On a cartesian plane, a unit circle is

  • a circle of radius 1,
  • centered at the origin (0, \, 0).

The circle crosses the x- and y-axis at four points:

  • (1, \, 0),
  • (0, \, 1),
  • (-1,\, 0), and
  • (0,\, -1).

Join a point on the circle with the origin using a segment. The "angle" here likely refers to the counter-clockwise angle between the positive x-axis and that segment.

When the angle is equal to 0^\circ, the segment overlaps with the positive x-axis. The point is on both the circle and the positive x-axis. Its coordinates would be (1, \, 0).

To locate the point with a 90^{\circ} angle, rotate the 0^\circ segment counter-clockwise by 90^{\circ}. The segment would land on the positive y-axis. In other words, the 90^{\circ}-point would be at the intersection of the positive y-axis and the circle. Its coordinates would be (0, \, 1).

4 0
3 years ago
Divide. check your answer
slava [35]

Step-by-step explanation:

:)..................

7 0
2 years ago
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