Answer:
Step-by-step explanation:
just simplify the LHS first.
You can either multiply 1/5 by (x+3) and then solve
or
multiply both sides by 5 to get rid of 1/5 on LHS
I will multiply by 5
(x+3)= -10x-15 ( 5*1/5(x+3)= -5(2x+3)
now rearrange the equation
x+3=-10x-15
-10x-15-x-3=0
-11x-17=0
-11x=17
x= -17/11
Given that 
and 
, we can say the following:
Now, remember what happens if we have a negative square root: it becomes an imaginary number. We don't want this, so we want to make sure whatever is under a square root is greater than 0 (given we are talking about real numbers only).
Thus, let's set what is under both square roots to be greater than 0:
Since both of the square roots are in the same function, we want to take the union of the domains of the individual square roots to find the domain of the overall function.
Now, let's look back at the function entirely, which is:
Since 
is on the bottom of the fraction, we must say that 
, since the denominator can't equal 0. Thus, we must exclude 
from the domain.
Thus, our answer is Choice C, or 
.
<em>If you are wondering why the choices begin with the 
symbol, it is because this is a way of representing that 
lies within a particular set.</em>
Hello,
P=0.72^(3/2)=0.610940...years=223.1398...days
Answer:
A
Step-by-step explanation:
If you have to add 2 to X to get it back to the original, it started out 2 to the left. (It would seem like it ought to be C, but when you add an subtract from the x value in functions, it's opposite of what you might think.)
