Is there a photo for this problem? I solved what i coulda. givenb. givenc. def. of supplementary angles (i think)d.photo to support this?
e.
The slope of the given line is -1/3. The perpendicular line's slope is the opposite reciprocal of the given line's slope. So, the perpendicular line's slope is 3. Then we have slope intercept form y=mx+b
y=3x+b
We don't know "b" which is the y-intercept for this equation, but we have the coordinates (6, -1). We can use these to find the slope by plugging them into the equation.
-1=3(6)+b
-1=18+b
-1-18=18+b-18
-19=b
So, the resulting y-intercept is -19.
The final perpendicular equation would be y=3x-19
Answer:
D. 8/15
Step-by-step explanation:
Answer:
=5 11/36(Decimal: 5.305556)
Step-by-step explanation:
389+1512
=359+1512
=359+1712
=19136
=5 11/36
Answer:
Step-by-step explanation:
The formula to calculate the forecast could be determine by using the exponential smoothing method :
![Ft = F(t-1) + \alpha [A(t-1) - F(t-1)]](https://tex.z-dn.net/?f=Ft%20%3D%20F%28t-1%29%20%2B%20%20%5Calpha%20%5BA%28t-1%29%20-%20F%28t-1%29%5D)
Where ,Ft is the Forecast for period t
F(t-1) is the Forecast for the period previous to t
A(t-1) is the Actual demand for the period previous to t
= Smoothing constant
To get the forecast for may and june the above formula with
and april forecast of 500 will be used
For march

For April

For May

So forecast for May = 536.25