Price of movie ticket in Japan is x=7.362$
Price of movie ticket in Switzerland is y=13.652$
Step-by-step explanation:
Let, Price of movie ticket in Japan is x
Price of movie ticket in Switzerland is y
Statement 1 : Total of 79.39$ of three movie ticket in Japan and two movie ticket in Switzerland
We write, 3x+2y=79.39 ( Equation 1 )
Statement 1 : Total of 75.68$ of two movie ticket in Japan and three movie ticket in Switzerland
We write, 2x+3y=75.68 ( Equation 2 )
Solving by method of elimination
Multiplying equation 1 by 2, we get
6x+4y=158.78
Multiplying equation 2 by 3, we get
6x+9y=227.04
Subtracting both the linear equation,
6x+4y=158.78
- 6x+9y=227.04
_______________
0x-5y=(158.78-227.04)
-5y=(-68.26)
5y=68.26
y=13.652$
Replacing value of y in any equation
3x+2y=79.39
3x+2(13.652 )=79.39
x=17.362$
Thus,
Price of movie ticket in Japan is x=7.362$
Price of movie ticket in Switzerland is y=13.652$
Answer:
a
Step-by-step explanation:
Answer:
Step-by-step explanation:
♨Rage♨
Answer:
A. 4
B. Point-slope: y - 5600 = 40(x-0)
Slope-intercept: y = 40x +5600
Standard: y - 40x = 5600
C. g(x) = 40x + 5600
D. 5880
Step-by-step explanation:
Part A
m = (y2-y1)/(x2-x1)
m = (5720-5600)/(3-0)
m = (120)/(3)
m = 40
Part B
Point-slope: y - 5600 = 40(x-0)
Slope-intercept: y = 40x +5600
Standard: y - 40x = 5600
Part C
g(x) = 40x + 5600
Part D
g(x) = 40(7) + 5600
g(x) = 280 + 5600 = 5880
