Using the normal distribution, it is found that Sue will get a letter grade of B.
In a <em>normal distribution </em>with mean 
and standard deviation 
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem, Sue got a grade of 0.85, hence 
.
- Looking at the z-table, z = 0.85 has a p-value of 0.8023, hence she is approximately in the top 20%, which is below the top 15% but above the top 50%, hence she got a letter grade of B.
A similar problem is given at brainly.com/question/25745464
A) interquartile range
The difference between the upper and the lower quartile is a measure of spread known as the interquartile range.
4x - 3(x - 2) - x
4x - 3x + 6 - x
4x - 4x + 6
6....u r correct because ur x's cancel out
Each person was to have 1.5 pounds of turkey, but, with the extra people she would have to buy an additional 4.5 pounds of turkey. If she didn’t buy anymore turkey then everyone would get 1.25 pounds of turkey, which is about 1/6 less of what they would have originally gotten. 1/6 is equal to 16.7% or 0.167.
Answer:
B 35%
Step-by-step explanation:
35/100 reduces to .35. To turn this into a percent, multiply it by 100 and add a percent sign. .35 * 100 = 35. 35%
