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nalin [4]
3 years ago
8

How do you write 60% as a decimal?​

Mathematics
2 answers:
schepotkina [342]3 years ago
8 0

Answer:

0.6

Step-by-step explanation:

Pavlova-9 [17]3 years ago
3 0
0.6 my guy hope this helps
You might be interested in
List and explain the elements that make up the structure of a fugue, then list and explain at least four techniques Bach utilize
mina [271]

Answer:

The fugue begins with an exposure. After the exhibition the alternative composer between episodes and presentations of the subject. In each fugue this scheme is developed in a varied way according to the invention and the needs of the composer.

Step-by-step explanation:

The elements that make up a musical fugue are:

The exhibition: It begins with one of the voices presenting the subject (name given to the theme on which a fugue is based). A second voice continues with the answer. The other voices continue alternately between subjects and responses. The exhibition concludes once all the voices have presented the subject or the answer.

While the second voice presents the answer the first voice makes a counterpoint to this answer. Similarly, when the third voice enters, the first two accompany it with other counterpoints. This counterpoint can be called counterpoint or free counterpoint. It is called a countersubject when it appears next to the answer. When the counterpoint is different in each presentation it is known as a free counterpoint.

The final section of the fugue begins when the subject returns to the initial hue of the fugue and from here to the end of the work. This ending is usually formed in several measures added to the main structure. This conclusion is the coda.

In the first place, he must remember that Bach was a self-taught, he was trained alone and specifically by the study of music itself, by the observation and analysis of other people's compositions, very often of poor significance in front of his own and that he copied, however, of his handwriting. The pedagogical activity of Bach and what he taught: "We must make the fugue of the subject", this means that each subject requires his fugue. Bach added another teaching, "voices must not enter without having something to say, or call before they have said everything they have to say," which means that they have voices should not speak for speaking and that they have no obligation to be always present.

In conclusion, Bach did not give any norm about the fugue, not least in terms of the genre of procedures for cases where this kind of compositions could be applied, leaving subjects free to perform this type of music.

6 0
3 years ago
Yesterday the student councils bank account balance was -$54.31. Today the balance is $65.10. What is the change in dollars in t
uysha [10]
-$69.68 is your answer if I hope that this is correct.
3 0
2 years ago
John, Sally, and Natalie would all like to save some money. John decides that it
brilliants [131]

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2)  y=100x+300

Part 3) \$12,300

Part 4) \$2,700

Part 5) Is a exponential growth function

Part 6) A=6,000(1.07)^{t}

Part 7) \$11,802.91

Part 8)  \$6,869.40

Part 9) Is a exponential growth function

Part 10) A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}

Part 11)  \$13,591.41

Part 12) \$6,107.01

Part 13)  Natalie has the most money after 10 years

Part 14)  Sally has the most money after 2 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

y=mx+b

The slope is equal to

m=\$100\ per\ month

The y-intercept or initial value is

b=\$300

so

y=100x+300

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

see part 1)

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

so

10\ years=10(12)=120 months

For x=120 months

substitute in the linear equation

y=100(120)+300=\$12,300

Part 4) How much money will John have after 2 years?

Remember that

1 year is equal to 12 months

so

2\  years=2(12)=24\ months

For x=24 months

substitute in the linear equation

y=100(24)+300=\$2,700

Part 5) What type of exponential model is Sally’s situation?

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt} 

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

P=\$6,000\\ r=7\%=0.07\\n=1

substitute in the formula above

A=6,000(1+\frac{0.07}{1})^{1*t}\\  A=6,000(1.07)^{t}

therefore

Is a exponential growth function

Part 6) Write the model equation for Sally’s situation

see the Part 5)

Part 7) How much money will Sally have after 10 years?

For t=10 years

substitute  the value of t in the exponential growth function

A=6,000(1.07)^{10}=\$11,802.91 

Part 8) How much money will Sally have after 2 years?

For t=2 years

substitute  the value of t in the exponential growth function

A=6,000(1.07)^{2}=\$6,869.40

Part 9) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt} 

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

P=\$5,000\\r=10\%=0.10

substitute in the formula above

A=5,000(e)^{0.10t}

Applying property of exponents

A=5,000(1.1052)^{t}

 therefore

Is a exponential growth function

Part 10) Write the model equation for Natalie’s situation

A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}

see Part 9)

Part 11) How much money will Natalie have after 10 years?

For t=10 years

substitute

A=5,000(e)^{0.10*10}=\$13,591.41

Part 12) How much money will Natalie have after 2 years?

For t=2 years

substitute

A=5,000(e)^{0.10*2}=\$6,107.01

Part 13) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

Part 14) Who will have the most money after 2 years?

Compare the final investment after 2 years of John, Sally, and Natalie

Sally has the most money after 2 years

3 0
3 years ago
I wanna finish this hw but I don't know how to do it pls teach me
tresset_1 [31]

Answer:

y 16

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the value of A when we rewrite... (PLZ HELP QUICK)
Marina86 [1]

Answer:

<h2>\frac{133}{8}</h2>

Step-by-step explanation:

Given,

{( \frac{5}{2} )}^{x}  +  {( \frac{5}{2} )}^{x + 3}

=  {( \frac{5}{2}) }^{x}  +  {( \frac{5}{2}) }^{x}  \times  {( \frac{5}{2} )}^{3}

= ( \frac{5}{2} ) ^{x} (1 +  {( \frac{5}{2} )}^{3}

=  {( \frac{5}{2} )}^{x} (1 +  \frac{125}{8} )

=  {( \frac{5}{2} )}^{x} ( \frac{1 \times 8 + 125}{8} )

=  {( \frac{5}{2}) }^{x} ( \frac{8 + 125}{8} )

{( \frac{5}{2} )}^{x} ( \frac{133}{8} )

Comparing with A • {( \frac{5}{2}) }^{x}

A = \frac{133}{8}

Hope this helps...

Good luck on your assignment...

7 0
3 years ago
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