Answer: 13.7
Step-by-step explanation: I used the pythagoream theorum.
- the probability that a person has the virus given that they have tested positive is 0.0151.
- the probability that a person does not have the virus given that they have tested negative is 0.9999
P(A) = 1/600 = 0.0017
P(B) = 0.9 * 0.0017 + 0.1 * (1 - 0.0017) = 0.1014
A) P (has the virus | tested positive) = P (tested positive | has the virus) ×
P (has the virus)/ P (tested positive)
= 0.9 × 0.0017/0.1014
= 0.0151
B) P (does not have the virus | tested negative) = P (tested negative | does not have the virus) × P (does not have the virus)/ P (tested negative)
= (1 - 0.1) *× (1 - 0.0017)/ (1 - 0.1014)
= 0.9999
Probability is the department of mathematics regarding numerical descriptions of ways likely an occasion is to occur, or how possibly it's far that a proposition is genuine. The possibility of an occasion varies between zero and 1, wherein, roughly speaking, 0 suggests the impossibility of the occasion and 1 shows certainty. The better the possibility of an event, the more likely it is that the event will arise.
A simple instance is the tossing of an honest (unbiased) coin. since the coin is truthful, the 2 results ("heads" and "tails") are both equally likely; the possibility of "heads" equals the chance of "tails"; and considering the fact that no different results are feasible, the possibility of both "heads" or "tails" is 1/2 (that could additionally be written as 0.5 or 50%).
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Step-by-step explanation:
let f(x) be y
∴ y = 10x/9 +11
(y - 11 )× 9/ 10 = x
Interchange x->y and y->x
(x - 11)×9/10 = y
here y is your f⁻¹(x)
∴ f⁻¹(x) = (x - 11 )× 9/10
or, f⁻¹(x) = 9x/10 - 99/10
Option (D) is correct
