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Anit [1.1K]
3 years ago
9

How do you write 0.12 as a fraction

Mathematics
1 answer:
Arturiano [62]3 years ago
7 0

[ Answer ]

\boxed{\frac{3}{25} }

[ Explanation ]

Rewrite 0.12 As A Fraction

-----------------------------

Rewrite Decimal As A Fraction With 1 As A Denominator

0.12 = \frac{0.12}{1}

Multiply To Remove Decimal Places

\frac{0.12}{1} · \frac{100}{100} = \frac{12}{100}

Find GCF, Reduce Fraction

\frac{12 \ / \ 4}{100 \ / \ 4} = \frac{3}{25}

0.12 = \frac{3}{25}

\boxed{\boxed{[ \ Eclipsed \ ]}}

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Step-by-step explanation:

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The side length of a square is x+1. write an expression that is equivalent to the perimeter of the square.
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using a table of values determine the solution to the equation below to the nearest fourth of a unit.
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Please prove this........​
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<u>Step-by-step explanation:</u>

Given: A + B + C = π    →     C = π - (A + B)

                                    → sin C = sin(π - (A + B))       cos C = sin(π - (A + B))

                                    → sin C = sin (A + B)              cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS:                        (sin 2A + sin 2B) + sin 2C

\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C

\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C

\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C

\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)

\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]

\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B

\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C    \checkmark

7 0
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